mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
159 lines
4.4 KiB
C++
159 lines
4.4 KiB
C++
// 最大可能的节点数
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const int MAXN = 100010;
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// 每个打标记的操作就是更新这个节点的信息,然后对子节点打标记
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struct Node {
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Node *ch[2], *p; int size, value;
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bool rev;
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inline bool dir(void) {return p->ch[1] == this;}
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inline void SetC(Node *x, bool d) {
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ch[d] = x; x->p = this;
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}
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inline void Rev(void) {
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swap(ch[0], ch[1]); rev ^= 1;
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}
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// null永远不会push
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inline void Push(void) {
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if (rev) {
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ch[0]->Rev();
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ch[1]->Rev();
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rev = 0;
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}
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}
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// null永远不会update
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inline void Update(void) {
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size = ch[0]->size + ch[1]->size + 1;
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}
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inline void initInfo(void) {
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rev = 0;
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}
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}Tnull, *null = &Tnull, *data, POOL[MAXN];
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class Splay {public:
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Node *root;
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inline void rotate(Node *x) {
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Node *p = x->p; bool d = x->dir();
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p->Push(); x->Push();
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p->p->SetC(x, p->dir());
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p->SetC(x->ch[!d], d);
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x->SetC(p, !d);
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p->Update();
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}
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inline void splay(Node *x, Node *G) {
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if (G == null) root = x;
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while (x->p != G) {
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if (x->p->p == G) rotate(x); else {
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if (x->dir() == x->p->dir()) {rotate(x->p); rotate(x);}
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else {rotate(x); rotate(x);}
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}
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}
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x->Push();
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x->Update();
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}
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inline Node* Renew(int value) {
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Node *ret = data++;
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ret->ch[0] = ret->ch[1] =ret->p = null;
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ret->size = 1; ret->value = value;
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ret->initInfo();
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return ret;
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}
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inline Node* getMin(Node *x) {Node *tmp = x; while (tmp->ch[0] != null) tmp = tmp->ch[0]; return tmp;}
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inline Node* getMax(Node *x) {Node *tmp = x; while (tmp->ch[1] != null) tmp = tmp->ch[1]; return tmp;}
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// 查询第k大
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inline Node* getKth(int k) {
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Node *tmp = root;
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assert(k > 0 && k <= root->size);
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while (true) {
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tmp->Push();
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if (tmp->ch[0]->size + 1 == k) return tmp;
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if (tmp->ch[0]->size >= k) tmp = tmp->ch[0];
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else k -= tmp->ch[0]->size + 1, tmp = tmp->ch[1];
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}
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}
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// 以下为splay当作平衡树使用
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// 查找树中value = v的元素, 返回之后splay
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inline Node* find(int v) {
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Node *tmp = root;
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while (tmp != null) {
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tmp->Push();
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if (tmp->value == v) return tmp;
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if (v < tmp->value) tmp = tmp->ch[0]; else tmp = tmp->ch[1];
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}
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return null;
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}
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// 统计有多少元素小于等于v, 当flag = 1时,统计多少元素严格小于v, 一定要记得splay最后的那个tmp
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inline int Count(int v, bool flag = 0) {
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Node *tmp = root, *last = null; int ret = 0;
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while (tmp != null) {
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tmp->Push();
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last = tmp;
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if ((!flag && tmp->value > v) || (flag && tmp->value >= v)) {
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tmp = tmp->ch[0];
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} else ret += tmp->ch[0]->size + 1, tmp = tmp->ch[1];
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}
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if (last != null) splay(last, null);
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return ret;
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}
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// 删除x这个结点
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inline void erase(Node* x) {
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splay(x, null);
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if (x->ch[0] == null || x->ch[1] == null) {
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int d = x->ch[1] != null;
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root = x->ch[d]; root->p = null;
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return;
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}
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Node *L = getMax(x->ch[0]), *R = getMax(x->ch[1]);
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splay(L, x); splay(R, x);
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L->SetC(R, 1); L->p = null; root = L;
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L->Update();
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}
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// 插入一个值为value的节点,初始要以Insert(root, null, value)来调用, 返回之后splay
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inline Node* Insert(Node *&now, Node* father, int value) {
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if (now == null) {
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now = Renew(value); now->p = father;
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return now;
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}
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Node *ret;
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now->Push();
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if (value <= now->value) ret = Insert(now->ch[0], now, value);
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else ret = Insert(now->ch[1], now, value);
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now->Update();
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return ret;
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}
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// 以下为splay维护序列, 初始要在原序列中放入一个-inf和inf来防止边界条件
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// 得到原数列中[l,r]区间对应的结点,如果l == r + 1则表示是一个空区间
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inline Node* getInterval(int l, int r) {
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assert(l <= r + 1);
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Node *L = getKth(l), *R = getKth(r + 2);
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splay(L, null); splay(R, L);
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return R->ch[0];
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}
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// 删除一段区间[l,r]
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inline void eraseInterval(int l, int r) {
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getInterval(l, r);
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root->ch[1]->ch[0] = null;
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root->ch[1]->Update();
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root->Update();
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}
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// 在位置l的后面插入一段区间x (0 <= l <= n)
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inline void insertInterval(int l, Node *x) {
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Node *L = getKth(l + 1), *R = getKth(l + 2);
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splay(L, null); splay(R, L);
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R->SetC(x, 0);
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R->Update(); L->Update();
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}
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// 把数列a的[l,r]构建为一个splay
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inline Node* Build(int l, int r, int a[]) {
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if (l > r) return null;
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int mid = (l + r) >> 1;
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Node *ret = Renew(a[mid]);
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if (l == r) return ret;
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ret->SetC(Build(l, mid - 1, a), 0);
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ret->SetC(Build(mid + 1, r, a), 1);
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ret->Update();
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return ret;
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}
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}T;
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void clear(void) {
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data = POOL;
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T.root = null;
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}
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