mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
c14ecbe72c
3400-3499
105 lines
2.8 KiB
C++
105 lines
2.8 KiB
C++
#include<iostream>
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#include<cstring>
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#include<map>
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#include<algorithm>
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#include<stack>
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#include<queue>
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#include<cstring>
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#include<cmath>
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#include<string>
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#include<cstdlib>
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#include<vector>
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#include<cstdio>
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#include<set>
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#include<list>
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#include<numeric>
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#include<cassert>
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#include<sstream>
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#include<ctime>
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#include<bitset>
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#include<functional>
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using namespace std;
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typedef pair<int, int> pii;
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int day[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
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bool isLeap(long long year)
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{
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return year % 400 == 0 || year % 4 == 0 && year % 100 != 0;
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}
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vector<pii> ht;
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vector<string> pvt[10];
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vector<string> leapVt[10];
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int sum[10];
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int rev(int t)
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{
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char str[10];
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sprintf(str, "%04d", t);
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reverse(str, str+4);
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return atoi(str);
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}
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void init()
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{
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for (int mm = 1; mm <= 12; mm++) {
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for (int dd = 1; dd <= day[mm]; dd++) {
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if (dd % 10 == 0) continue;
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int t = mm*100 + dd;
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ht.push_back(pii(rev(t), t));
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}
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}
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sort(ht.begin(), ht.end());
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long long now = 9220;
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for (int n = 0; n <= 7; n++, now *= 10) {//9220*..*0229
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if (n == 0) {
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pvt[n].push_back("");
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leapVt[n].push_back("");
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} else if (n == 1) {
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for (char i = '0'; i <= '9'; i++) {
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pvt[n].push_back(string(1, i));//
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int year = now+(i-'0');
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if (isLeap(year)) {
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leapVt[n].push_back(pvt[n].back());
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}
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}
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} else {
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int nn = n - 2;
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for (char i = '0'; i <= '9'; i++) {
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for (vector<string>::iterator it = pvt[nn].begin(); it != pvt[nn].end(); it++) {
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pvt[n].push_back(i+*it+i);
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long long year = now+atoi(pvt[n].back().c_str());
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if (isLeap(year)) {
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leapVt[n].push_back(pvt[n].back());
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}
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}
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}
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}
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sum[n] = 330*pvt[n].size() + leapVt[n].size();
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}
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}
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int main()
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{
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init();
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int T, k, n;
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for (scanf("%d", &T); T--; ) {
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scanf("%d", &k);
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k--;
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for (n = 0; n <= 7; n++) {
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if (k < sum[n]) break;
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else k -= sum[n];
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}
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int num = pvt[n].size();
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if (k >= 322*num) {
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k -= 322*num;
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if (k < leapVt[n].size()) {
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printf("9220%s0229\n", leapVt[n][k].c_str());
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} else {
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k -= leapVt[n].size();
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int p = k/num + 322;
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printf("%d%s%04d\n", ht[p].first, pvt[n][k%num].c_str(), ht[p].second);
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}
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} else {
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int p = k/num;
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printf("%d%s%04d\n", ht[p].first, pvt[n][k%num].c_str(), ht[p].second);
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}
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}
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return 0;
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}
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