mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
ff9985fa25
3700-3799
134 lines
3.3 KiB
C++
134 lines
3.3 KiB
C++
#include <iostream>
|
|
#include <algorithm>
|
|
#include <cstring>
|
|
#include <string>
|
|
#include <cstdio>
|
|
#include <cmath>
|
|
#include <queue>
|
|
#include <map>
|
|
#include <set>
|
|
#define MAXN 100005
|
|
#define MAXM 400005
|
|
#define INF 1000000011
|
|
#define lch(x) x<<1
|
|
#define rch(x) x<<1|1
|
|
#define lson l,m,rt<<1
|
|
#define rson m+1,r,rt<<1|1
|
|
#define eps 1e-7
|
|
using namespace std;
|
|
bool tag[10001];
|
|
int p[10001];
|
|
int cnt;
|
|
void get_prime()
|
|
{
|
|
cnt = 0;
|
|
tag[1] = 1;
|
|
for (int i = 2; i < 10000; i++)
|
|
{
|
|
if (!tag[i])
|
|
p[cnt++] = i;
|
|
for (int j = 0; j < cnt && p[j] * i < 10000; j++)
|
|
{
|
|
tag[i*p[j]] = 1;
|
|
if (i % p[j] == 0)
|
|
break;
|
|
}
|
|
}
|
|
}
|
|
int n, m;
|
|
int a[11005], b[11005];
|
|
int numa[10005], numb[10005];
|
|
int ans[1000005];
|
|
int num[1001111];
|
|
void get(int *x, int n, int *num)
|
|
{
|
|
for(int i = 1; i <= n; i++)
|
|
{
|
|
for(int j = 0; j < cnt; j++)
|
|
{
|
|
int tn = x[i];
|
|
if(tn < p[j]) break;
|
|
while(tn){num[j] += tn / p[j]; tn /= p[j];}
|
|
}
|
|
}
|
|
}
|
|
bool ok()
|
|
{
|
|
for(int i = 0; i < cnt; i++)
|
|
if(numb[i] > numa[i]) return 0;
|
|
return 1;
|
|
}
|
|
int main()
|
|
{
|
|
int T;
|
|
get_prime();
|
|
scanf("%d", &T);
|
|
while(T--)
|
|
{
|
|
scanf("%d%d", &n, &m);
|
|
for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
|
|
for(int i = 1; i <= m; i++) scanf("%d", &b[i]);
|
|
memset(numa, 0, sizeof(numa));
|
|
memset(numb, 0, sizeof(numb));
|
|
get(a, n, numa);
|
|
get(b, m, numb);
|
|
if(!ok())
|
|
{
|
|
printf("-1\n");
|
|
continue;
|
|
}
|
|
for(int i = 0; i < cnt; i++) numa[i] -= numb[i];
|
|
int tp = 0;
|
|
memset(num, 0, sizeof(num));
|
|
while(1)
|
|
{
|
|
int low = 2, high = 10006;
|
|
int can = 0;
|
|
while(low <= high)
|
|
{
|
|
int mid = (low + high) >> 1;
|
|
int fg = 1;
|
|
for(int j = 0; j < cnt; j++)
|
|
{
|
|
int tn = mid;
|
|
if(tn < p[j]) break;
|
|
int sum = 0;
|
|
while(tn){sum += tn / p[j]; tn /= p[j];}
|
|
if(sum > numa[j])
|
|
{
|
|
fg = 0;
|
|
break;
|
|
}
|
|
}
|
|
if(fg) {low = mid + 1; can = max(can, mid);}
|
|
else high = mid - 1;
|
|
}
|
|
int x = can;
|
|
if(x == 0) break;
|
|
ans[tp] = x;
|
|
int ot = INF;
|
|
for(int j = 0; j < cnt; j++)
|
|
{
|
|
int tn = x;
|
|
if(tn < p[j]) break;
|
|
int sum = 0;
|
|
while(tn){sum += tn / p[j]; tn /= p[j];}
|
|
if(sum > 0) ot = min(ot, numa[j] / sum);
|
|
}
|
|
num[tp] += ot;
|
|
tp++;
|
|
for(int j = 0; j < cnt; j++)
|
|
{
|
|
int tn = x;
|
|
if(tn < p[j]) break;
|
|
int sum = 0;
|
|
while(tn){sum += tn / p[j]; tn /= p[j];}
|
|
numa[j] -= ot * sum;
|
|
}
|
|
}
|
|
printf("%d\n", tp);
|
|
for(int i =0; i < tp; i++) printf("%d %d\n", ans[i], num[i]);
|
|
}
|
|
return 0;
|
|
}
|