mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
88 lines
1.3 KiB
C++
88 lines
1.3 KiB
C++
#include<iostream>
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#include<cstring>
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using namespace std;
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int d[100][100]; //d[i][j]表示输入字符串从下标i到下标j至少需要加的括号数
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int c[100][100]={-1}; //c[i][j]表示从下标i到下标j的子串分割的下标,-1表示不分割
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int len; //输入括号串的长度
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string s; //输入的括号串
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void dp()
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{
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int i,j,k,l;
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int min;
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for(i=0; i<len; i++) d[i][i]=1;
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for(l=1; l<len; ++l)
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for(i=0; i+l<len; ++i)
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{
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j=i+l;
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min=d[i][i]+d[i+1][j];
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c[i][j]=i;
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for(k=i+1; k<j; k++)
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{
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if(d[i][k]+d[k+1][j]<min)
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{
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min=d[i][k]+d[k+1][j];
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c[i][j]=k;
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}
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}
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d[i][j]=min;
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if(s[i]=='(' && s[j]==')' || s[i]=='[' && s[j]==']')
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{
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if(d[i+1][j-1] < min)
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{
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d[i][j]=d[i+1][j-1];
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c[i][j]=-1;
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}
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}
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}
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}
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void print(int i, int j) //打印结果
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{
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if(i>j) return;
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if(i==j)
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{
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if(s[i]=='(' || s[i]==')') cout<<"()";
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else cout<<"[]";
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}
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else
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{
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if(c[i][j]>=0) //从i到j从c[i][j]处分割
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{
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print(i, c[i][j]);
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print(c[i][j]+1, j);
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}
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else
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{
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if(s[i]=='(')
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{
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cout<<"(";
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print(i+1, j-1);
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cout<<")";
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}
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else
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{
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cout<<"[";
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print(i+1, j-1);
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cout<<"]";
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}
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}
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}
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}
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int main()
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{
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cin>>s; //输入括号序列
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len=s.size();
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dp();
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print(0, len-1);
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cout<<endl;
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return 0;
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}
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