mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
53497060fc
4300-4399
165 lines
3.8 KiB
C++
165 lines
3.8 KiB
C++
#include <string.h>
|
|
#include <algorithm>
|
|
#include <math.h>
|
|
#include <stdio.h>
|
|
using namespace std;
|
|
typedef long long LL;
|
|
const int N=210;
|
|
const int M=41000;
|
|
const int MOD=1000000007;
|
|
const double eps=1e-8;
|
|
const double PI=acos(-1.0);
|
|
const double PI2=PI*2;
|
|
struct Point
|
|
{
|
|
double x,y;
|
|
LL index;
|
|
double angle;
|
|
inline void input()
|
|
{
|
|
scanf("%lf%lf",&x,&y);
|
|
}
|
|
}point[N],temp[N];
|
|
int n;
|
|
bool visit[M];
|
|
LL fib[M];
|
|
LL fk[M];
|
|
int num[N][N];
|
|
int left[N][N];
|
|
int right[N][N];
|
|
inline Point operator-(const Point &a, const Point &b)
|
|
{
|
|
Point c;
|
|
c.x=a.x-b.x;
|
|
c.y=a.y-b.y;
|
|
return c;
|
|
}
|
|
inline double operator*(const Point &a, const Point &b)
|
|
{
|
|
return a.x*b.y-a.y*b.x;
|
|
}
|
|
inline bool operator==(const Point &a, const Point &b)
|
|
{
|
|
return a.x==b.x&&a.y==b.y;
|
|
}
|
|
inline int cross(const Point &a, const Point &b, const Point &o)
|
|
{
|
|
return (a-o)*(b-o)>0? 1:-1;
|
|
}
|
|
inline int cross(const int &a, const int &b, const int &o)
|
|
{
|
|
return cross(point[a],point[b],point[o]);
|
|
}
|
|
inline double positiveAtan(const Point &a, const Point &o)
|
|
{
|
|
double res=atan2(a.y-o.y,a.x-o.x);
|
|
if(res<0)
|
|
res+=PI2;
|
|
return res;
|
|
}
|
|
bool operator<(const Point &a, const Point &b)
|
|
{
|
|
return a.angle<b.angle;
|
|
}
|
|
int abs1(int x)
|
|
{
|
|
return x<0? -x:x;
|
|
}
|
|
int getAngleNumber(int a,int b,int c)
|
|
{
|
|
if(point[c].y<point[b].y&&point[a].y>=point[b].y)
|
|
return n-abs1(right[b][c]-right[b][a]+2)+3;
|
|
return abs1(right[b][a]-right[b][c])+2;
|
|
}
|
|
int getTriangleNumber(int a, int b, int c)
|
|
{
|
|
return n-left[a][b]-left[b][c]-left[c][a]+getAngleNumber(a,b,c)+getAngleNumber(b,c,a)+getAngleNumber(c,a,b)-6;
|
|
}
|
|
LL quick_mod(LL a,LL b)
|
|
{
|
|
LL ans=1;
|
|
a%=MOD;
|
|
while(b)
|
|
{
|
|
if(b&1)
|
|
{
|
|
ans=ans*a%MOD;
|
|
b--;
|
|
}
|
|
b>>=1;
|
|
a=a*a%MOD;
|
|
}
|
|
return ans;
|
|
}
|
|
LL solve(int x)
|
|
{
|
|
if(visit[x])
|
|
return fk[x];
|
|
visit[x]=true;
|
|
fib[0]=x;
|
|
fib[1]=x;
|
|
for(int i=2;i<=x;++i)
|
|
fib[i]=(fib[i-1]*fib[i-2])%MOD;
|
|
return fk[x]=fib[x]+1;
|
|
}
|
|
int main()
|
|
{
|
|
while(~scanf("%d",&n))
|
|
{
|
|
for(int i=0;i<n;++i)
|
|
{
|
|
point[i].input();
|
|
temp[i]=point[i];
|
|
temp[i].index=i;
|
|
}
|
|
memset(left,0,sizeof(left));
|
|
memset(right,0,sizeof(right));
|
|
for(int i=0;i<n;++i)
|
|
{
|
|
for(int j=i+1;j<n;++j)
|
|
{
|
|
for(int k=0;k<n;++k)
|
|
{
|
|
if(k!=i&&k!=j)
|
|
{
|
|
if(cross(k,j,i)<0)
|
|
++left[i][j];
|
|
else if(cross(k,i,j)<0)
|
|
++left[j][i];
|
|
}
|
|
}
|
|
}
|
|
for(int j=0;j<n;++j)
|
|
{
|
|
if(temp[j].index==i)
|
|
temp[j].angle=-1e100;
|
|
else
|
|
temp[j].angle=positiveAtan(temp[j],point[i]);
|
|
}
|
|
sort(temp,temp+n);
|
|
int cnt=0;
|
|
for(int j=0;j<n;++j)
|
|
right[i][temp[j].index]=++cnt;
|
|
}
|
|
memset(num,0,sizeof(num));
|
|
for(int i=0;i<n;++i)
|
|
{
|
|
for(int j=i+1;j<n;++j)
|
|
{
|
|
for(int k=0;k<n;++k)
|
|
{
|
|
if(k==i||k==j) continue;
|
|
if(cross(point[k], point[j], point[i]) < 0)
|
|
num[i][j]+=getAngleNumber(j,k,i)-getTriangleNumber(i,j,k);
|
|
}
|
|
}
|
|
}
|
|
LL ans=1;
|
|
for(int i=0;i<n;++i)
|
|
for(int j=i+1;j<n;++j)
|
|
ans=(ans*solve(num[i][j]))%MOD;
|
|
printf("%I64d\n", ans);
|
|
}
|
|
return 0;
|
|
}
|