53 lines
1.1 KiB
C++
53 lines
1.1 KiB
C++
#include<stdio.h>
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#include<string.h>
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#define lson l, m, rt<<1
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#define rson m+1, r, rt<<1|1
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#define mid int m = (l + r)>>1
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#define maxn 200000
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int sum[maxn<<2],pos[maxn],val[maxn],ans[maxn<<2];//ans储存插入的值；
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void push_up(int rt)
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{
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sum [rt] = sum[rt<<1]+sum[rt<<1|1];
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}
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void build(int l, int r, int rt)
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{
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sum[rt]=r-l+1;
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if(l == r)return;
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mid;
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build(lson);
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build(rson);
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}
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void update(int pos, int val, int l, int r, int rt)
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{
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if(l == r){ans[rt]=val;sum[rt]--;return;}
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mid;
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if(pos <= sum[rt<<1])update(pos, val, lson); //根据左右儿子空位的多少和插入数据的位置比较来确定插入哪个儿子
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else update(pos -sum[rt<<1], val, rson);
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push_up(rt);
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}
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void print(int l, int r, int rt)
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{
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if(l == r){printf("%d ",ans[rt]);return;}
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mid;
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print(lson);
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print(rson);
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}
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int main()
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{
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int n,i;
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while(~scanf("%d",&n))
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{
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for(i=0;i<n;i++)
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scanf("%d%d",&pos[i],&val[i]);
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build(1, n ,1);
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for(i=n-1;i>=0;i--)
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update(pos[i]+1, val[i], 1, n, 1);
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print(1, n, 1);
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printf("\n");
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}
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return 0;
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}
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