95 lines
2.3 KiB
C++
95 lines
2.3 KiB
C++
#include<cstdio>
|
|
#include<algorithm>
|
|
using namespace std;
|
|
const int N =102;
|
|
const int mod = 1000000007;
|
|
int h;
|
|
struct matrix
|
|
{
|
|
int row,col;
|
|
int m[N][N];
|
|
void init(int row,int col)
|
|
{
|
|
this->row = row;
|
|
this->col = col;
|
|
for(int i=0; i<=row; ++i)
|
|
for(int j=0; j<=col; ++j)
|
|
m[i][j] = 0;
|
|
}
|
|
} A,pm[33],ans;
|
|
matrix operator*(const matrix & a,const matrix& b)
|
|
{
|
|
matrix res;
|
|
res.init(a.row,b.col);
|
|
for(int k=1; k<=a.col; ++k)
|
|
{
|
|
for(int i=1; i<= res.row; ++i)
|
|
{
|
|
if(a.m[i][k] == 0 ) continue;
|
|
for(int j = 1; j<=res.col; ++j)
|
|
{
|
|
if(b.m[k][j] == 0 ) continue;
|
|
res.m[i][j] = (1LL *a.m[i][k]*b.m[k][j] + res.m[i][j])%mod;
|
|
}
|
|
}
|
|
}
|
|
return res;
|
|
}
|
|
void cal(int x)
|
|
{
|
|
for(int i=0; i<=31; ++i)
|
|
if(x & (1<<i) ) ans = pm[i]*ans;
|
|
}
|
|
void getPm()
|
|
{
|
|
pm[0] = A;
|
|
for(int i=1; i<=31; ++i)
|
|
pm[i] = pm[i-1]*pm[i-1];
|
|
}
|
|
struct sp
|
|
{
|
|
int nk,tk;
|
|
int ck[N];
|
|
bool operator<(const sp & o)const
|
|
{
|
|
return nk<o.nk;
|
|
}
|
|
} p[N];
|
|
int main()
|
|
{
|
|
int n,m,q,t,f[N],c[N],kase=0;
|
|
while(~scanf("%d%d%d",&n,&m,&q))
|
|
{
|
|
for(int i=m; i>0; --i) scanf("%d",&f[i]);
|
|
scanf("%d",&t);
|
|
h =t;
|
|
for(int i=1; i<=t; ++i) scanf("%d",&c[i]);
|
|
for(int i=0; i<q; ++i)
|
|
{
|
|
scanf("%d%d",&p[i].nk,&p[i].tk);
|
|
if(p[i].tk > h) h = p[i].tk;
|
|
for(int j=1; j<=p[i].tk; ++j) scanf("%d",&p[i].ck[j]);
|
|
}
|
|
sort(p,p+q);
|
|
A.init(h,h);
|
|
for(int i=1; i<=t; ++i) A.m[1][i] = c[i];
|
|
for(int i=2; i<=h; ++i) A.m[i][i-1] = 1;
|
|
getPm();
|
|
ans.init(h,1);
|
|
for(int i = m; i > 0; --i) ans.m[i][1] = f[i];
|
|
int last=m;
|
|
for(int i=0; i<q; ++i)
|
|
{
|
|
if( p[i].nk <=last || p[i].nk >n ) continue;
|
|
cal( p[i].nk-last-1);
|
|
last = p[i].nk;
|
|
for(int j=1; j<=p[i].tk; ++j) A.m[1][j] = p[i].ck[j];
|
|
for(int j=p[i].tk+1; j<=h; ++j) A.m[1][j] = 0;
|
|
ans =A*ans;
|
|
}
|
|
cal(n-last);
|
|
printf("Case %d: %d\n",++kase,ans.m[1][1]);
|
|
}
|
|
return 0;
|
|
}
|