115 lines
2.5 KiB
C++
115 lines
2.5 KiB
C++
#include <iostream>
|
|
#include <cstdio>
|
|
#include <cstring>
|
|
#include <algorithm>
|
|
#include <cmath>
|
|
#include <queue>
|
|
using namespace std;
|
|
const int N = 2000009;
|
|
int visit[N];
|
|
struct node{
|
|
int a[5];
|
|
} re[N];
|
|
int ans[N];
|
|
int map[4][4];
|
|
void makemap(int k)
|
|
{
|
|
for(int i=0;i<3;i++)
|
|
for(int j=0;j<3;j++)
|
|
{
|
|
map[i][j]=k%5;
|
|
k/=5;
|
|
}
|
|
}
|
|
struct quenod{
|
|
int s,step;
|
|
};
|
|
queue<quenod> que;
|
|
bool v[5];
|
|
bool oor(int x,int y)
|
|
{
|
|
if(x<0||x>2) return false;
|
|
if(y<0||y>2) return false;
|
|
return true;
|
|
}
|
|
int dx[]={0,0,-1,1};
|
|
int dy[]={-1,1,0,0};
|
|
bool ok(int x,int y,int n)
|
|
{
|
|
memset(v,0,sizeof(v));
|
|
int tx,ty;
|
|
for(int i=0;i<4;i++)
|
|
{
|
|
tx = x+dx[i],ty=y+dy[i];
|
|
if(!oor(tx,ty)) continue;
|
|
v[map[tx][ty]]=true;
|
|
}
|
|
for(int i=1;i<n;i++)
|
|
if(!v[i]) return false;
|
|
return true;
|
|
}
|
|
int cnt = 1;
|
|
int zip[]={1,5,25,125,625,3125,15625,78125,390625,1953125};
|
|
void init()
|
|
{
|
|
while(!que.empty()) que.pop();
|
|
quenod e,t;
|
|
e.s=0;e.step=0;
|
|
que.push(e);
|
|
visit[0] = true;
|
|
while(!que.empty())
|
|
{
|
|
e = que.front();que.pop();
|
|
makemap(e.s);
|
|
for(int i=0;i<3;i++)
|
|
for(int j=0;j<3;j++)
|
|
{
|
|
for(int k=map[i][j]+1;k<5;k++)
|
|
if(ok(i,j,k))
|
|
{
|
|
t.s = e.s+zip[i*3+j]*(k-map[i][j]);
|
|
if(visit[t.s])continue;
|
|
visit[t.s] = true;
|
|
memset(re[cnt].a,0,sizeof(re[cnt].a));
|
|
for(int ii=0;ii<3;ii++)
|
|
for(int jj=0;jj<3;jj++)
|
|
if(map[ii][jj]) re[cnt].a[map[ii][jj]]++;
|
|
re[cnt].a[map[i][j]]--;
|
|
re[cnt].a[k]++;
|
|
t.step=e.step+1;
|
|
ans[cnt]=t.step;
|
|
cnt++;
|
|
que.push(t);
|
|
}
|
|
}
|
|
}
|
|
}
|
|
int main()
|
|
{
|
|
init();
|
|
int a[5],w,sum,T=1;
|
|
while(~scanf("%d",&a[1])&&a[1])
|
|
{
|
|
for(int i=2;i<5;i++)scanf("%d",&a[i]);
|
|
scanf("%d",&w);
|
|
bool ou = false;
|
|
for(int i=0;i<cnt;i++)
|
|
{
|
|
sum=0;
|
|
for(int j=1;j<5;j++)
|
|
sum+=re[i].a[j]*a[j];
|
|
if(sum>=w)
|
|
{
|
|
ou = true;
|
|
printf("Case %d: %d\n",T++,ans[i]);
|
|
break;
|
|
}
|
|
}
|
|
if(!ou)
|
|
{
|
|
printf("Case %d: Impossible\n",T++);
|
|
}
|
|
}
|
|
return 0;
|
|
}
|