#include #include #include #include #include #include #include #include #include #define MAXN 100005 #define MAXM 400005 #define INF 1000000011 #define lch(x) x<<1 #define rch(x) x<<1|1 #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define eps 1e-7 using namespace std; bool tag[10001]; int p[10001]; int cnt; void get_prime() { cnt = 0; tag[1] = 1; for (int i = 2; i < 10000; i++) { if (!tag[i]) p[cnt++] = i; for (int j = 0; j < cnt && p[j] * i < 10000; j++) { tag[i*p[j]] = 1; if (i % p[j] == 0) break; } } } int n, m; int a[11005], b[11005]; int numa[10005], numb[10005]; int ans[1000005]; int num[1001111]; void get(int *x, int n, int *num) { for(int i = 1; i <= n; i++) { for(int j = 0; j < cnt; j++) { int tn = x[i]; if(tn < p[j]) break; while(tn){num[j] += tn / p[j]; tn /= p[j];} } } } bool ok() { for(int i = 0; i < cnt; i++) if(numb[i] > numa[i]) return 0; return 1; } int main() { int T; get_prime(); scanf("%d", &T); while(T--) { scanf("%d%d", &n, &m); for(int i = 1; i <= n; i++) scanf("%d", &a[i]); for(int i = 1; i <= m; i++) scanf("%d", &b[i]); memset(numa, 0, sizeof(numa)); memset(numb, 0, sizeof(numb)); get(a, n, numa); get(b, m, numb); if(!ok()) { printf("-1\n"); continue; } for(int i = 0; i < cnt; i++) numa[i] -= numb[i]; int tp = 0; memset(num, 0, sizeof(num)); while(1) { int low = 2, high = 10006; int can = 0; while(low <= high) { int mid = (low + high) >> 1; int fg = 1; for(int j = 0; j < cnt; j++) { int tn = mid; if(tn < p[j]) break; int sum = 0; while(tn){sum += tn / p[j]; tn /= p[j];} if(sum > numa[j]) { fg = 0; break; } } if(fg) {low = mid + 1; can = max(can, mid);} else high = mid - 1; } int x = can; if(x == 0) break; ans[tp] = x; int ot = INF; for(int j = 0; j < cnt; j++) { int tn = x; if(tn < p[j]) break; int sum = 0; while(tn){sum += tn / p[j]; tn /= p[j];} if(sum > 0) ot = min(ot, numa[j] / sum); } num[tp] += ot; tp++; for(int j = 0; j < cnt; j++) { int tn = x; if(tn < p[j]) break; int sum = 0; while(tn){sum += tn / p[j]; tn /= p[j];} numa[j] -= ot * sum; } } printf("%d\n", tp); for(int i =0; i < tp; i++) printf("%d %d\n", ans[i], num[i]); } return 0; }