/* 中国象棋棋盘,Alice有一个帅,Bob有一个将和一个马。如果Alice赢,输出 "Lucky guy!",否则就输出"Lose in x steps T.T!",x表示从开始到结束双方走的步数和。 一方获胜当且仅当自己的将(帅被对方吃掉)。特别注意,如果出现平局我们认为Alice获胜。 Alice如果知道自己无法取胜就会尽量让比赛进行更多的步数。双方采取最优策略。 */ #include #include #include #include #include #include #include #include #include using namespace std; #define maxn 105 const int move_ma[8][2] = {///马移动 {-2, -1}, {-2, 1}, {-1, -2}, {1, -2}, {-1, 2}, {1, 2}, {2, -1}, {2, 1} }; const int no[4][2] = {///马脚 {-1, 0}, {0, -1}, {0, 1}, {1, 0} }; const int move_shuai[4][2] = {///将移动 {1, 0}, {-1, 0}, {0, 1}, {0, -1} }; int Max[maxn][10][10], cnt[maxn][10][10]; int vis[maxn][10][10][2]; ///敌马的位置 敌将位置 我将位置 0:我先手 1:敌先手 ///状态下的失败步数 ///0表示我必胜 int out[maxn][10][10]; ///我先走 这个状态后继状态中有多少种合法状态 struct node { int a, b, c;///马位置 敌将位置 我将位置 int id;///0:我先手 1:敌先手 int step;///这个状态下失败的步数 node (int _a, int _b, int _c, int _id, int _s) { a = _a, b = _b, c = _c, id = _id, step = _s; } }; queue q; bool balk (int now, int next, int i, int j) { int x = now/9, y = now%9; int xx = next/9, yy = next%9; //cout << x << " " << y << endl; //cout << xx << " " << yy << endl; for (int k = 0; k < 8; k++) { if (xx == x+move_ma[k][0] && yy == y+move_ma[k][1]) { //cout << k << endl; int xxx = x+no[k/2][0], yyy = y+no[k/2][1]; //cout << xxx << " " << yyy << endl; if (xxx == i/3+7 && yyy == i%3+3) return 1; if (xxx == j/3 && yyy == j%3+3) return 1; } } return 0; } void bfs () { while (!q.empty ()) { node now = q.front (); q.pop (); int x = now.c/3, y = now.c%3;///我帅 int ma_x = now.a/9, ma_y = now.a%9;///敌马 if (now.id == 0) {///这一步是我先手 上一步是敌先手 for (int i = 0; i < 4; i++) {///敌走将 int xx = now.b/3+move_shuai[i][0], yy = now.b%3+move_shuai[i][1];///上一步敌将的位置 if (xx < 0 || xx >= 3 || yy < 0 || yy >= 3) continue; if (vis[now.a][xx*3+yy][now.c][1] != -1) continue; if (xx+7 == ma_x && yy+3 == ma_y) continue;///敌将和马不重合 vis[now.a][xx*3+yy][now.c][1] = now.step+1; q.push (node (now.a, xx*3+yy, now.c, 1, now.step+1)); } for (int i = 0; i < 8; i++) { int xx = ma_x+move_ma[i][0], yy = ma_y+move_ma[i][1]; if (xx < 0 || xx >= 10 || yy < 0 || yy >= 9) continue; if (vis[xx*9+yy][now.b][now.c][1] != -1) continue; if (xx == now.b/3+7 && yy == now.b%3+3) continue;///敌将和马不重合 if (xx == x && yy == y+3) continue;///敌马和我帅不重合 if (balk (xx*9+yy, now.a, now.b, now.c)) continue;///马脚 vis[xx*9+yy][now.b][now.c][1] = now.step+1; q.push (node (xx*9+yy, now.b, now.c, 1, now.step+1)); } } else {///上一步是我先手 for (int i = 0; i < 4; i++) { int xx = x+move_shuai[i][0], yy = y+move_shuai[i][1];///上一步我的位置 if (xx < 0 || xx >= 3 || yy < 0 || yy >= 3) continue; if (vis[now.a][now.b][xx*3+yy][0] != -1) continue; if (xx == ma_x && yy+3 == ma_y) continue;///上一步不可能重合 Max[now.a][now.b][xx*3+yy] = max (Max[now.a][now.b][xx*3+yy], now.step); if (++cnt[now.a][now.b][xx*3+yy] == out[now.a][now.b][xx*3+yy]) { vis[now.a][now.b][xx*3+yy][0] = Max[now.a][now.b][xx*3+yy]+1; q.push (node (now.a, now.b, xx*3+yy, 0, vis[now.a][now.b][xx*3+yy][0])); } } } } } int relation (int x, int y, int i, int j, int who) { ///0:我必败 1:我必胜 2:不一定 int x1 = i/3, y1 = i%3;///敌将 int x2 = j/3, y2 = j%3;///我帅 y1 += 3, y2 += 3; if (y1 == y2) {///两王相对(中间没有马) 胜负立分 if (y == y1) { if (x > x1+7 || x < x2) { if (who == 0) return 1; return 0; } else return 2; } if (who == 0) return 1; else return 0; } if (who == 1) { int d1 = abs (x-x2), d2 = abs (y-y2); if ((d1 == 1 && d2 == 2) || (d1 == 2 && d2 == 1)) return 0;///被敌马吃掉 return 2; } ///马被吃 if (x > 2 || y < 3 || y > 5) return 2;//马在外面 if (y == y2) { if (x2-x == 1) {///在我将的下侧 return 1; } if (x-x2 == 1) {///在我将的上侧 if (y1 == y) return 2;///有敌将的保护 return 1; } return 2; } if (x == x2 && abs (y-y2) == 1 && y <= 5 && y >= 3) {///在我将的左右侧 if (y1 == y) return 2;///有敌方将的保护 return 1; } return 2; } void init () { while (!q.empty ()) q.pop (); memset (vis, -1, sizeof vis); memset (Max, 0, sizeof Max); memset (out, 0, sizeof out); memset (cnt, 0, sizeof cnt); for (int x = 0; x < 10; x++) for (int y = 0; y < 9; y++) {///敌马位置 for (int i = 0; i < 9; i++) {///敌将位置 for (int j = 0; j < 9; j++) {///我将位置 if ((y-3 == j%3 && x == j/3) || (y-3 == i%3 && x-7 == i/3)) continue;///马和将重合 int res0 = relation (x, y, i, j, 0); int res1 = relation (x, y, i, j, 1); if (!res0) vis[x*9+y][i][j][0] = 1, q.push (node (x*9+y, i, j, 0, 1)); else if (res0 == 1) vis[x*9+y][i][j][0] = 0; if (!res1) vis[x*9+y][i][j][1] = 1, q.push (node (x*9+y, i, j, 1, 1)); else if (res1 == 1) vis[x*9+y][i][j][1] = 0; for (int k = 0; k < 4; k++) {///我先走 int next_x = j/3+move_shuai[k][0], next_y = j%3+move_shuai[k][1]; if (next_x < 0 || next_x >= 3 || next_y < 0 || next_y >= 3) continue; if (next_x == x && next_y+3 == y) continue;///和马重合的状态已经计算过了 out[x*9+y][i][j]++; } } } } bfs (); } int x, y, xx, yy, xxx, yyy; int main () { //freopen ("in", "r", stdin); //freopen ("out", "w", stdout); init (); int t; //cout << balk (21, 32, 0, 7) << endl; //cout << vis[30][1][6][1] << endl; //cout << vis[0][0][0][0] << endl; cin >> t; int who; //输入敌马 敌将 我将坐标 先手的人 while (t--) { cin >> x >> y >> xx >> yy >> xxx >> yyy >> who; xx -= 7, yy -= 3; yyy -= 3; int res = vis[x*9+y][xx*3+yy][xxx*3+yyy][who]; if (res == 0) { cout << "Lucky guy!" << endl; } else cout << "Lose in " << res << " steps T.T!" << endl; } return 0; }