Create 3254.cpp

POJ/3254.cpp

@@ -0,0 +1,108 @@
+#include <cstdio>
+#include <cstring>
+#include <cstdlib>
+#include <algorithm>
+using namespace std;
+
+#define MOD 100000000
+
+#define _BITMOVE(x) (1<<x)
+#define _BITMAX(x) _BITMOVE(x)
+#define _BITMAXVALUE(x) (_BITMAX(x)-1)u
+
+#define MAXLINE 13
+#define MAXSTATUS _BITMAX(MAXLINE)
+
+typedef unsigned long STATE;
+STATE map[MAXLINE];
+int dp[MAXLINE][MAXSTATUS];
+STATE availableStatus[MAXSTATUS];
+
+
+inline STATE HasNeighbor(STATE x)
+{
+    return x&(x<<1);
+}
+
+inline STATE PlaceOnMap(int line,int stateid)
+{
+    return map[line]&availableStatus[stateid];
+}
+
+inline STATE CheckBetweenLines(int line1,int line2)
+{
+    return availableStatus[line1]&availableStatus[line2];
+}
+void init()
+{
+
+}
+void solve(int n,int m)
+{
+    for(int i=0;i<n;i++)
+    {
+        STATE thisline=0;
+        for(int j=0;j<m;j++)
+        {
+            int tmp;
+            scanf("%d",&tmp);
+            thisline=(thisline<<1)|tmp;
+        }
+        map[i]=~thisline;
+    }
+    ///求所有保证两头牛不相邻的状态
+    int statusCount=-1;
+    for(int ci=0;ci<_BITMAX(m);ci++)
+    {
+        if(!HasNeighbor(ci))
+        {
+            availableStatus[++statusCount]=ci;
+        }
+    }
+    ///重要！
+    ++statusCount;
+    /// Initialize the Line 0 . Check all available status.
+    for(int ci=0;ci<statusCount;ci++)
+    {
+        if(!PlaceOnMap(0,ci))
+        {
+            dp[0][ci]=1;
+        }
+    }
+    /// Main DP
+    for(int i=1;i<n;i++)
+    {
+        for(int j=0;j<statusCount;j++)
+        {
+            ///不能使用序号为j的放置方法
+            if(PlaceOnMap(i,j)) continue;
+            ///纵向检查
+            for(int k=0;k<statusCount;k++)
+            {
+                ///上一行使用序号为j的放置方法是没用的
+                if(PlaceOnMap(i-1,k)) continue;
+                ///检查两行之间是否有相邻
+                if(!CheckBetweenLines(k,j))
+                {
+                    ///没有的话可以加上
+                    dp[i][j]+=dp[i-1][k];
+                }
+            }
+        }
+    }
+    ///将最后一行加起来
+    int ans=0;
+    for(int ci=0;ci<statusCount;ci++)
+    {
+        ans=(ans+dp[n-1][ci])%MOD;
+    }
+    printf("%d\n",ans);
+}
+
+int main()
+{
+    int n,m;
+    scanf("%d %d",&n,&m);
+    solve(n,m);
+    return 0;
+}