Kiritow
/
OJ-Problems-Source
mirror of https://github.com/Kiritow/OJ-Problems-Source
1
0
Fork 0
Code Issues Projects Releases Wiki Activity

Merge pull request #1 from Kiritow/master 

Catch up with Kiritow
pull/2/head
KiritoTRw 2016-04-27 18:34:08 +08:00
parent 4257b1e5fb fb085e0082
commit 8fedca2bcb
25 changed files with 1477 additions and 1 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

57
HDOJ/1078.cpp Normal file
View File

@ -0,0 +1,57 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
#define MAXN 101
int map[MAXN][MAXN];
int dp[MAXN][MAXN];
int N;
int K;
int dfs(int y,int x)
{
if(dp[y][x]!=0) return dp[y][x];
dp[y][x]=map[y][x];
for(int i=1;i<=K;i++)
{
if(x+i<N&&map[y][x]<map[y][x+i])
{
dp[y][x]=max(dp[y][x],dfs(y,x+i)+map[y][x]);
}
if(x-i>=0&&map[y][x]<map[y][x-i])
{
dp[y][x]=max(dp[y][x],dfs(y,x-i)+map[y][x]);
}
if(y+i<N&&map[y][x]<map[y+i][x])
{
dp[y][x]=max(dp[y][x],dfs(y+i,x)+map[y][x]);
}
if(y-i>=0&&map[y][x]<map[y-i][x])
{
dp[y][x]=max(dp[y][x],dfs(y-i,x)+map[y][x]);
}
}
return dp[y][x];
}
int main()
{
int n,k;
while(scanf("%d %d",&n,&k)==2&&n!=-1&&k!=-1)
{
memset(dp,0,sizeof(int)*MAXN*MAXN);
memset(map,0,sizeof(int)*MAXN*MAXN);
N=n;
K=k;
for(int i=0;i<N;i++)
{
for(int j=0;j<N;j++)
{
scanf("%d",&map[i][j]);
}
}
int ans=dfs(0,0);
printf("%d\n",ans);
}
return 0;
}

92
HDOJ/1166.cpp Normal file
View File

@ -0,0 +1,92 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
int C[131072];
char cmd[32];
int getsum(int left,int right,int pos,int leftbound,int rightbound)
{
if(left<=leftbound&&right>=rightbound)
{
return C[pos];
}
if(right<leftbound||left>rightbound)
{
return 0;
}
int a=getsum(left,right,2*pos+1,leftbound,(leftbound+rightbound)/2);
int b=getsum(left,right,2*pos+2,(leftbound+rightbound)/2+1,rightbound);
return a+b;
}
int main()
{
int t;
scanf("%d",&t);
for(int itt=1;itt<=t;itt++)
{
printf("Case %d:\n",itt);
int N;
scanf("%d",&N);
int realn=1;
while(realn<N)
{
realn*=2;
}
memset(C,0,sizeof(int)*realn);
for(int i=0;i<N;i++)
{
scanf("%d",&C[realn-1+i]);
}
int start=(realn-1)/2;
while(start>0)
{
int L=start+1;
for(int i=0;i<L;i++)
{
C[start+i]=C[2*(start+i)+1]+C[2*(start+i)+2];
}
start=(start-1)/2;
}
C[0]=C[1]+C[2];
while(scanf("%s",cmd)==1)
{
if(strcmp(cmd,"End")==0)
{
break;
}
int a,b;
scanf("%d %d",&a,&b);
if(strcmp(cmd,"Query")==0)
{
int ans=getsum(a-1,b-1,0,0,realn-1);
printf("%d\n",ans);
}
else if(strcmp(cmd,"Add")==0)
{
int pos=realn-1+a-1;
while(pos>0)
{
C[pos]+=b;
pos=(pos-1)/2;
}
C[0]+=b;
}
else if(strcmp(cmd,"Sub")==0)
{
int pos=realn-1+a-1;
while(pos>0)
{
C[pos]-=b;
pos=(pos-1)/2;
}
C[0]-=b;
}
}
}/// end of for(...)
return 0;
}

42
HDOJ/1501_CSDN_dfs.cpp Normal file
View File

@ -0,0 +1,42 @@
#include <cstdio>
#include <cstring>
//#define LOCAL
using namespace std;
const int MAXN=205;
char a[MAXN],b[MAXN],all[2*MAXN-5];
int lenA,lenB,lenAll;
bool DFS(int posA,int posB,int posAll) {
if(posA==lenA&&posB==lenB)
return true;
if(posA<lenA&&a[posA]==all[posAll]&&DFS(posA+1,posB,posAll+1))
return true;
if(posB<lenB&&b[posB]==all[posAll]&&DFS(posA,posB+1,posAll+1))
return true;
return false;
}
int main()
{
#ifdef LOCAL
freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
#endif
int T,cnt=0;
scanf("%d",&T);
while(T--) {
printf("Data set %d: ",++cnt);
scanf("%s%s%s",a,b,all);
lenA=strlen(a);
lenB=strlen(b);
lenAll=strlen(all);
if((all[0]!=a[0]&&all[0]!=b[0])||(all[lenAll-1]!=a[lenA-1]&&all[lenAll-1]!=b[lenB-1])) {//剪枝，不加上就会TLE
printf("no\n");
continue;
}
printf("%s\n",DFS(0,0,0)?"yes":"no");
}
return 0;
}

36
HDOJ/1501_CSDN_dp.cpp Normal file
View File

@ -0,0 +1,36 @@
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
int n,m,al,bl,cl,lim;
char a[205],b[205],c[405];
bool dp[205][205];//dp[i][j]表示串a的前i个字符与串b的前j个字符是否能形成串c的前i+j个字符
int main() {
int T,kase=0;
scanf("%d",&T);
while(kase<T) {
scanf("%s%s%s",a+1,b+1,c+1);
al=strlen(a+1);
bl=strlen(b+1);
cl=al+bl;
memset(dp,false,sizeof(dp));
dp[0][0]=true;
for(int k=1;k<=cl;++k) {//枚举串c的字符
lim=min(k,al);
for(int i=max(1,k-bl);i<=lim;++i) {//在a串上进行状态转移
if(dp[i-1][k-i]&&a[i]==c[k])//如果串a前i-1个字符与串b前k-i个字符能构成串c的前k个字符，并且当前a[i]==c[k]
dp[i][k-i]=true;
}
lim=min(k,bl);
for(int j=max(1,k-al);j<=lim;++j) {//在b串上进行状态转移
if(dp[k-j][j-1]&&b[j]==c[k])//如果串a前k-j个字符与串b前j-1个字符能构成串c的前k个字符，并且当前b[j]==c[k]
dp[k-j][j]=true;
}
}
printf("Data set %d: %s\n",++kase,dp[al][bl]?"yes":"no");
}
return 0;
}

59
HDOJ/1501_dfs.cpp Normal file
View File

@ -0,0 +1,59 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
char a[300];
char b[300];
char c[700];
int lena,lenb,lenc;
bool dfs(int pos_in_a,int pos_in_b,int pos_in_c)
{
if(pos_in_a==lena&&pos_in_b==lenb)
{
return true;
}
if(pos_in_a<lena&&a[pos_in_a]==c[pos_in_c]&&dfs(pos_in_a+1,pos_in_b,pos_in_c+1))
{
return true;
}
if(pos_in_b<lenb&&b[pos_in_b]==c[pos_in_c]&&dfs(pos_in_a,pos_in_b+1,pos_in_c+1))
{
return true;
}
return false;
}
int main()
{
int t;
scanf("%d",&t);
for(int tt=1;tt<=t;tt++)
{
scanf("%s %s %s",a,b,c);
printf("Data set %d: ",tt);
lena=strlen(a);
lenb=strlen(b);
lenc=strlen(c);
if(a[0]!=c[0]&&b[0]!=c[0])
{
printf("no\n");
continue;
}
if(a[lena-1]!=c[lenc-1]&&b[lenb-1]!=c[lenc-1])
{
printf("no\n");
continue;
}
bool ans=dfs(0,0,0);
if(ans)
{
printf("yes\n");
}
else
{
printf("no\n");
}
}
return 0;
}

105
POJ/3040.cpp Normal file
View File

@ -0,0 +1,105 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <vector>
#include <algorithm>
using namespace std;
struct cash
{
int value;
int amount;
};
bool cmp(const cash& a,const cash& b)
{
return a.value<b.value;
}
int need[64];
int makedayfrom(vector<cash>& vec,int C)
{
memset(need,0,sizeof(int)*64);
int N=vec.size();
int left=C;
for(int i=N-1;i>=0;i--)
{//
if(vec.at(i).amount>0&&left>0)
{
int x=left/vec.at(i).value;
x=min(x,vec.at(i).amount);
need[i]=x;
left-=x*vec.at(i).value;
}
}
if(left>0)
{
for(int i=0;i<N;i++)
{
if(vec.at(i).amount>need[i]&&left>0)
{
int x=left/vec.at(i).value;
if(x==0)
{
/// try to make x = 1
need[i]++;
left=0;
break;
}
}
}
}
if(left>0)
{
return -1;
}
int canpayday=2<<29;
for(int i=0;i<64;i++)
{
if(need[i]>0)
{
canpayday=min(canpayday,vec.at(i).amount/need[i]);
}
}
if(canpayday<=0) return -1;
for(int i=0;i<N;i++)
{
if(need[i]>0)
{
vec.at(i).amount-=canpayday*need[i];
}
}
return canpayday;
}
int main()
{
int N,C;
scanf("%d %d",&N,&C);
vector<cash> vec;
int ans=0;
for(int i=0;i<N;i++)
{
cash s;
scanf("%d %d",&s.value,&s.amount);
vec.push_back(s);
}
sort(vec.begin(),vec.end(),cmp);
for(int i=N-1;i>=0;i--)
{
if(vec.at(i).value>=C)
{
ans+=vec.at(i).amount;
vec.pop_back();
}
else break;
}
int tmp;
while((tmp=makedayfrom(vec,C))>0)
{
ans+=tmp;
}
printf("%d\n",ans);
return 0;
}

72
POJ/3040_aiuxian.cpp Normal file
View File

@ -0,0 +1,72 @@
#include<stdio.h>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
const int maxn=30;
struct node
{
int x,y;//存储钱的大小和数量
bool operator<(const node c)const
{
return x>c.x;
}
}num[maxn];
int need[maxn],n,c,kj;
//need[]函数是是存储需要哪些钱币的组合
int main()
{
while(scanf("%d%d",&n,&c)!=EOF)
{
for(int i=0;i<n;i++)
scanf("%d%d",&num[i].x,&num[i].y);
sort(num,num+n);//排序是第一步
kj=0;
while(1)
{
int sum=c;
memset(need,0,sizeof(need));
for(int i=0;i<n;i++)//这个for循环是用于找出钱币的组合方法
{
if(sum>0)
{
int t=sum/num[i].x;
if(t==0)
continue;
t=min(t,num[i].y);
need[i]=t;
sum-=t*num[i].x;
}
}
if(sum>0)//如果在上面的组合中没有使sum变为0,则从小到大选择最小的面值组合，这样使面值超过的最小化
{
for(int i=n-1;i>=0;i--)
if(num[i].y&&num[i].x>=sum)
{
sum=0;
need[i]++;
break;
}
}
if(sum>0)//如果组合不能达到c，怎么说明搜索结束
break;
int cc=2e9;
for(int i=n-1;i>=0;i--)//找出这个组合成的面值中最小的数量，同时减去它们。
{
if(need[i])
{
cc=min(cc,num[i].y/need[i]);
}
}
kj+=cc;
for(int i=0;i<n;i++)
if(need[i])
{
num[i].y-=cc*need[i];
}
}
printf("%d\n",kj);
}
return 0;
}

102
POJ/3040_hankcs.cpp Normal file
View File

@ -0,0 +1,102 @@
#include <iostream>
#include <functional>
#include <algorithm>
#include <limits>
using namespace std;
typedef pair<int, int> Coin; // 硬币 面值和数量
Coin coin[20];
int need[20];
///////////////////////////SubMain//////////////////////////////////
int main(int argc, char *argv[])
{
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
#endif
int N, C;
cin >> N >> C;
for (int i = 0; i < N; ++i)
{
cin >> coin[i].first >> coin[i].second;
}
int week = 0;
// 面额不小于C的一定可以支付一周
for (int i = 0; i < N; ++i)
{
if (coin[i].first >= C)
{
week += coin[i].second;
coin[i].second = 0;
}
}
sort(coin, coin + N, greater<Coin>());
while(true)
{
int sum = C; // 等待凑足的sum
memset(need, 0, sizeof(need));
// 从大到小
for (int i = 0; i < N; ++i)
{
if (sum > 0 && coin[i].second > 0)
{
int can_use = min(coin[i].second,
sum / coin[i].first);
if (can_use > 0)
{
sum -= can_use * coin[i].first;
need[i] = can_use;
}
}
}
// 从小到大
for (int i = N - 1; i >= 0; --i)
{
if (sum > 0 && coin[i].second > 0)
{
int can_use = min(coin[i].second - need[i], // 上个loop用掉了一些
(sum + coin[i].first - 1) / coin[i].first); // 允许多出不超过一个面值的金额
if (can_use > 0)
{
sum -= can_use * coin[i].first;
need[i] += can_use;
}
}
}
if(sum > 0)
{
break;
}
int add_up = numeric_limits<int>::max(); // 凑起来的week数
// add_up多少个最优的week 受限于 每种面值能满足最优解下的需求个数多少次
for (int i = 0; i < N; ++i)
{
if (need[i] == 0)
{
continue;
}
add_up = min(add_up, coin[i].second / need[i]);
}
week += add_up;
// 最优解生效，更新剩余硬币数量
for (int i = 0; i < N; ++i)
{
if (need[i] == 0)
{
continue;
}
coin[i].second -= add_up * need[i];
}
}
cout << week << endl;
#ifndef ONLINE_JUDGE
fclose(stdin);
fclose(stdout);
system("out.txt");
#endif
return 0;
}
///////////////////////////End Sub//////////////////////////////////

81
POJ/3040_tuicool.cpp Normal file
View File

@ -0,0 +1,81 @@
#include <iostream>
#include<algorithm>
#include<math.h>
#include<stdio.h>
#include<string.h>
const int INF=0x3f3f3f3f;
using namespace std;
struct node
{
int val,mou;//面值和数目
} mon[25];
int n,c;
int need[25];//一种方案所需各面值的数目
bool cmp(node a,node b)
{
return a.val<b.val;
}
int main()
{
int i,ans,ti,rest,lim,mday;
while(~scanf("%d%d",&n,&c))
{
ans=0;
lim=-1;
for(i=0;i<n;i++)
scanf("%d%d",&mon[i].val,&mon[i].mou);
sort(mon,mon+n,cmp);
for(i=n-1;i>=0;i--)
if(mon[i].val>=c)//如果面值大于c直接加数目就行了
ans+=mon[i].mou;
else
{
lim=i;
break;
}
while(1)
{
memset(need,0,sizeof need);
rest=c;
for(i=lim;i>=0;i--)//尽可能用大面值凑够
{
if(!mon[i].mou||!rest)
continue;
ti=rest/mon[i].val;
ti=min(ti,mon[i].mou);
need[i]=ti;
rest-=ti*mon[i].val;
}
if(rest)//没凑够的话。只能往回找最小的面值凑够。保证损失的钱最少
{
for(i=0;i<=lim;i++)
{
if(mon[i].val>=rest&&(mon[i].mou-need[i]))
{
need[i]++;
rest=0;
break;
}
}
if(rest)
break;
}
mday=INF;
for(i=0;i<=lim;i++)
if(need[i])
mday=min(mday,mon[i].mou/need[i]);//得出该种方案能支付的最大周数
ans+=mday;
for(i=0;i<=lim;i++)
mon[i].mou-=mday*need[i];
}
printf("%d\n",ans);
}
return 0;
}
/*
11
6 1
4 1
*/

74
POJ/3190.cpp Normal file
View File

@ -0,0 +1,74 @@
#include <cstdio>
#include <functional>
#include <queue>
#include <algorithm>
using namespace std;
struct cow
{
int start,over;
int pos;
bool operator <(const cow& b) const
{
if(over==b.over)
return start>b.start;
return over>b.over;
}
};
bool cmp(const cow& a,const cow& b)
{
if(a.start==b.start) return a.over<b.over;
return a.start<b.start;
}
priority_queue<cow> bus;
int use[50001];
cow cowx[50001];
int cnt=1;
int main()
{
int n;
while(scanf("%d",&n)==1)
{
for(int i=0; i<n; i++)
{
int a,b;
scanf("%d %d",&a,&b);
cowx[i].start=a;
cowx[i].over=b;
cowx[i].pos=i;
}
sort(cowx,cowx+n,cmp);
use[cowx[0].pos]=1;
bus.push(cowx[0]);
for(int i=1; i<n; i++)
{
if(!bus.empty()&&bus.top().over<cowx[i].start)
{
use[cowx[i].pos]=use[bus.top().pos];
bus.pop();
}
else
{
++cnt;
use[cowx[i].pos]=cnt;
}
bus.push(cowx[i]);
}
printf("%d\n",cnt);
for(int i=0; i<n; i++)
{
printf("%d\n",use[i]);
}
}
return 0;
}

63
POJ/3190_csdn.cpp Normal file
View File

@ -0,0 +1,63 @@
#include<cstdio>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<queue>
using namespace std;
const int maxn=60000;
int n,use[maxn];
struct Node
{
int l;
int r;
int pos;
bool operator <(const Node &a)const
{
if(r==a.r)
return l>a.l;
return r>a.r;
}
}a[maxn];
priority_queue<Node> q;
bool cmp(Node a,Node b)
{
if(a.l==b.l)
return a.r<b.r;
return a.l<b.l;
}
int main()
{
while(scanf("%d",&n)!=EOF)
{
for(int i=0;i<n;i++)
{
scanf("%d%d",&a[i].l,&a[i].r);
a[i].pos=i;
}
sort(a,a+n,cmp);
q.push(a[0]);
int now=0,ans=1;
use[a[0].pos]=1;
for(int i=1;i<n;i++)
{
if(!q.empty()&&q.top().r<a[i].l)
{
use[a[i].pos]=use[q.top().pos];
q.pop();
}
else
{
ans++;
use[a[i].pos]=ans;
}
q.push(a[i]);
}
printf("%d\n",ans);
for(int i=0;i<n;i++)
printf("%d\n",use[i]);
while(!q.empty())
q.pop();
}
return 0;
}

2
README.md
View File

@ -1,4 +1,4 @@
[English](https://github.com/Kiritow/OJ-Problems-Source#oj-problems-source) | [中文(简体)](https://github.com/Kiritow/OJ-Problems-Source#oj问题源代码)
[English](#oj-problems-source) | [中文(简体)](#oj问题源代码)
# OJ-Problems-Source
Source of **AC** Problems on different OJ.
If you want to publish your source file, just contact me via GitHub~

59
RQNOJ/600.cpp Normal file
View File

@ -0,0 +1,59 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
#define MAXM 100000
#define MAXN 20000
struct ppk
{
    int a,b,c;
};
bool cmp(const ppk& a,const ppk& b)
{
    return a.c>b.c;
}
int f[MAXN*2];
ppk X[MAXM];
int get(int x)
{
    if(x==f[x]) return x;
    else
    {
        f[x]=get(f[x]);
        return f[x];
    }
}
int main()
{
    int n,m;
    scanf("%d %d",&n,&m);
    for(int i=1;i<=n*2;i++)
    {
        f[i]=i;
    }
    for(int i=0;i<m;i++)
    {
        scanf("%d %d %d",&X[i].a,&X[i].b,&X[i].c);
    }
    sort(X,X+m,cmp);
    for(int s=0;s<m;s++)
    {
        int x=get(X[s].a);
        int y=get(X[s].b);
        if(x==y)
        {
            printf("%d\n",X[s].c);
            return 0;
        }
        int w=get(X[s].a+n);
        int t=get(X[s].b+n);
        f[x]=t;
        f[y]=w;
}
    printf("0\n");
    return 0;
}

2
RQNOJ/Readme.md Normal file
View File

@ -0,0 +1,2 @@
#RenQing Net Online Judge (RQNOJ)
[RQNOJ Home Page](http://www.rqnoj.cn/ "Welcome to RQNOJ")

53
SDUSTOJ/1795_cnblogs.cpp Normal file
View File

@ -0,0 +1,53 @@
/* ***********************************************
Author :devil
Created Time :2016/4/26 16:10:39
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
typedef long long LL;
const int N=2e6+7;
int a[N],b[N];
long long sum[N];
int main()
{
//freopen("in.txt","r",stdin);
int n,x;
while(~scanf("%d",&n))
{
int ma=0;
memset(a,0,sizeof(a));
memset(b,0,sizeof(b));
memset(sum,0,sizeof(sum));
for(int i=0;i<n;i++)
{
scanf("%d",&x);
ma=max(ma,x);
a[x]++;
}
for(int i=1;i<=ma*2+1;i++)
{
sum[i]=sum[i-1]+a[i]*i;
b[i]=b[i-1]+a[i];
}
LL ans=1e12+10;
for(int i=1;i<=ma;i++)
{
LL now=sum[i-1];
for(int j=1;i*j<=ma;j++)
now=now+(b[i*(j+1)-1]-b[i*j-1])*j+sum[i*(j+1)-1]-sum[i*j]-(b[i*(j+1)-1]-b[i*j])*j*i;
ans=min(ans,now);
}
printf("%lld\n",ans);
}
return 0;
}

128
SDUSTOJ/1796_cnblogs.cpp Normal file
View File

@ -0,0 +1,128 @@
/* ***********************************************
Author :devil
Created Time :2016/4/26 13:11:52
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
const int N=100005;
int n,a[N],b[N],tree[N<<2];
void build1(int node,int l,int r)
{
if(l==r)
{
tree[node]=N;
return ;
}
int m=(l+r)>>1;
build1(node<<1,l,m);
build1(node<<1|1,m+1,r);
tree[node]=min(tree[node<<1],tree[node<<1|1]);
}
void update1(int node,int l,int r,int p)
{
if(l==r)
{
tree[node]=b[p];
return ;
}
int m=(l+r)>>1;
if(a[p]<=m) update1(node<<1,l,m,p);
else update1(node<<1|1,m+1,r,p);
tree[node]=min(tree[node<<1],tree[node<<1|1]);
}
int query1(int node,int l,int r,int p)
{
if(l>=p) return tree[node];
int m=(l+r)>>1,ans;
ans=query1(node<<1|1,m+1,r,p);
if(p<=m) ans=min(ans,query1(node<<1,l,m,p));
return ans;
}
void build2(int node,int l,int r)
{
if(l==r)
{
tree[node]=0;
return ;
}
int m=(l+r)>>1;
build2(node<<1,l,m);
build2(node<<1|1,m+1,r);
tree[node]=max(tree[node<<1],tree[node<<1|1]);
}
void update2(int node,int l,int r,int p)
{
if(l==r)
{
tree[node]=b[p];
return ;
}
int m=(l+r)>>1;
if(a[p]<=m) update2(node<<1,l,m,p);
else update2(node<<1|1,m+1,r,p);
tree[node]=max(tree[node<<1],tree[node<<1|1]);
}
int query2(int node,int l,int r,int p)
{
if(r<=p) return tree[node];
int m=(l+r)>>1,ans;
ans=query2(node<<1,l,m,p);
if(p>m) ans=max(ans,query2(node<<1|1,m+1,r,p));
return ans;
}
int main()
{
//freopen("in.txt","r",stdin);
while(~scanf("%d",&n))
{
int x,flag=1;
for(int i=1; i<=n; i++)
{
scanf("%d",&x);
a[x]=i;
}
for(int i=1; i<=n; i++)
{
scanf("%d",&x);
b[x]=i;
}
build1(1,1,n);
for(int i=n; i>0; i--)
{
if(a[i]<=b[i]&&b[i]>query1(1,1,n,a[i]))
{
flag=0;
break;
}
update1(1,1,n,i);
}
if(!flag)
{
printf("NO\n");
continue;
}
build2(1,1,n);
for(int i=1; i<=n; i++)
{
if(a[i]>=b[i]&&b[i]<query2(1,1,n,a[i]))
{
flag=0;
break;
}
update2(1,1,n,i);
}
if(!flag) printf("NO\n");
else printf("YES\n");
}
return 0;
}

93
SDUSTOJ/1799_cnblogs.cpp Normal file
View File

@ -0,0 +1,93 @@
/* ***********************************************
Author :devil
Created Time :2016/4/26 22:47:45
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
#define inf 0x3f3f3f3f
#define maxn 1010
struct node
{
int v,d;
node(int a=0,int b=0):v(a),d(b){}
bool operator < (const node &a) const
{
return d>a.d;
}
};
struct edge
{
int v,cost;
edge(int a=0,int b=0):v(a),cost(b){}
};
vector<edge> eg[maxn];
bool vis[maxn];
int n,m,s,a,b,t,c,dis[maxn],ss[maxn],tt[maxn];
void dijkstra(int x)
{
memset(vis,false,sizeof(vis));
for(int i=0; i<=n; i++)
dis[i]=inf;
priority_queue<node>q;
while(!q.empty()) q.pop();
dis[x]=0;
q.push(node(x,0));
node tmp;
while(!q.empty())
{
tmp=q.top();
q.pop();
int u=tmp.v;
if(vis[u]) continue;
vis[u]=true;
for(int i=0; i<eg[u].size(); i++)
{
int v=eg[tmp.v][i].v;
int cost=eg[u][i].cost;
if(!vis[v]&&dis[v]>dis[u]+cost)
{
dis[v]=dis[u]+cost;
q.push(node(v,dis[v]));
}
}
}
}
int main()
{
//freopen("in.txt","r",stdin);
while(~scanf("%d%d%d%d",&n,&m,&s,&t)&&n)
{
for(int i=1;i<=n;i++)
eg[i].clear();
while(m--)
{
scanf("%d%d%d",&a,&b,&c);
eg[a].push_back(edge(b,c));
eg[b].push_back(edge(a,c));
}
for(int i=1;i<=s;i++)
scanf("%d",&ss[i]);
for(int i=1;i<=t;i++)
scanf("%d",&tt[i]);
int ans=inf;
for(int i=1;i<=s;i++)
{
dijkstra(ss[i]);
for(int j=1;j<=t;j++)
ans=min(ans,dis[tt[j]]);
}
if(ans!=inf) printf("%d\n",ans);
else printf("What a pity!\n");
}
return 0;
}

50
SDUSTOJ/1800_cnblogs.cpp Normal file
View File

@ -0,0 +1,50 @@
/* ***********************************************
Author :devil
Created Time :2016/4/26 21:58:52
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
const int N=1010;
int dp[N],a[N],b[N],c[N];
int main()
{
//freopen("in.txt","r",stdin);
int t,n;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
for(int i=1; i<=n; i++)
scanf("%d",&a[i]);
int ma=0;
memset(c,0,sizeof(c));
c[1]=n;
for(int i=1; i<=n; i++)
{
b[i]=dp[i]=1;
for(int j=1; j<i; j++)
{
if(a[i]>a[j]&&dp[i]<dp[j]+1)
{
dp[i]=dp[j]+1;
b[i]=b[j];
}
else if(a[i]>a[j]&&dp[i]==dp[j]+1) b[i]+=b[j];
}
if(dp[i]>1) c[dp[i]]+=b[i];
ma=max(ma,dp[i]);
}
printf("%d\n",c[ma]);
}
return 0;
}

62
SDUSTOJ/1801_cnblogs.cpp Normal file
View File

@ -0,0 +1,62 @@
/* ***********************************************
Author :devil
Created Time :2016/4/26 22:18:57
************************************************ */
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
typedef long long LL;
const int N=110;
const int mod=1e9+9;
LL dp[N][N],dp2[N][N];
int a[N],b[N];
int main()
{
//freopen("in.txt","r",stdin);
int t,n,m;
scanf("%d",&t);
while(t--)
{
scanf("%d%d",&n,&m);
for(int i=1; i<=n; i++)
scanf("%d",&a[i]);
memset(dp,0,sizeof(dp));
memset(dp2,0,sizeof(dp2));
memset(b,-1,sizeof(b));
b[a[1]]=dp[a[1]][1]=1;
for(int i=2;i<=n;i++)
{
dp[a[i]][1]=1;
int mi=min(i,m);
for(int k=2;k<=mi;k++)
{
for(int j=1;j<a[i];j++)
{
dp[a[i]][k]+=dp[j][k-1];
if(dp[a[i]][k]>=mod) dp[a[i]][k]-=mod;
}
if(b[a[i]]!=-1)
{
dp[a[i]][k]-=dp2[a[i]][k];
if(dp[a[i]][k]<0) dp[a[i]][k]+=mod;
}
dp2[a[i]][k]=dp[a[i]][k];
}
b[a[i]]=i;
}
LL ans=0;
for(int i=1;i<=n;i++)
ans=(ans+dp[i][m])%mod;
printf("%lld\n",ans);
}
return 0;
}

69
SDUSTOJ/1802.cpp Normal file
View File

@ -0,0 +1,69 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
/*
bool check(int inc)
{
if(inc%36!=0) return false;
char buff[32];
memset(buff,0,32);
sprintf(buff,"%d",inc);
if(strstr(buff,"36")==NULL) return false;
int len=strlen(buff);
for(int i=0;i<len;i++)
{
if(buff[i]=='3')
{
if(buff[i+1]!='6') return false;
}
if(buff[i]=='6')
{
if(i==0) return false;
else if(buff[i-1]!='3') return false;
}
}
return true;
}
int cnt=0;
int main()
{
freopen("aaa.txt","w",stdout);
for(int i=1;i<=100000;i++)
{
if(check(i)) {
cnt++;printf("%d,",i);
}
}
printf("#%d",cnt);
return 0;
}
*/
int num[119]={36,360,936,1368,1836,2736,3600,3636,3672,4536,5364,5436,7236,8136,9036,9360,9936,10368,10836,11736,13608,13644,13680,14364,14436,17136,18036,18360,18936,19368,19836,20736,22536,23652,23688,25236,27036,27360,27936,28368,28836,29736,36000,36036,36072,36108,36144,36180,36252,36288,36360,36504,36540,36720,36792,36828,36900,36936,36972,40536,41364,41436,44136,45036,45360,45936,47736,49536,50364,50436,52236,53604,53640,54036,54360,54936,55368,55836,58536,59364,59436,70236,71136,72036,72360,72936,73620,73692,74736,77364,77436,79236,80136,81036,81360,81936,82368,82836,83628,85536,88236,89136,90036,90360,90936,91368,91836,92736,93600,93636,93672,94536,95364,95436,97236,98136,99036,99360,99936};
int main()
{
int T;
scanf("%d",&T);
for(int i=0;i<T;i++)
{
int L;
scanf("%d",&L);
bool found=false;
for(int k=0;k<119;k++)
{
if(num[k]<L) continue;
else
{
printf("%d\n",num[k]);
found=true;
break;
}
}
if(!found)
{
printf("-1\n");
}
}
return 0;
}

2
SDUSTOJ/Readme.md Normal file
View File

@ -0,0 +1,2 @@
#山东科技大学 SDUSTOJ
[Goto SDUSTOJ Home Page (May be changed since last update)](http://acm.zning.net/JudgeOnline/ "Welcome to SDUSTOJ")

59
TYVJ/1403.cpp Normal file
View File

@ -0,0 +1,59 @@
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
using namespace std;
#define MAXM 100000
#define MAXN 20000
struct ppk
{
int a,b,c;
};
bool cmp(const ppk& a,const ppk& b)
{
return a.c>b.c;
}
int f[MAXN*2];
ppk X[MAXM];
int get(int x)
{
if(x==f[x]) return x;
else
{
f[x]=get(f[x]);
return f[x];
}
}
int main()
{
int n,m;
scanf("%d %d",&n,&m);
for(int i=1;i<=n*2;i++)
{
f[i]=i;
}
for(int i=0;i<m;i++)
{
scanf("%d %d %d",&X[i].a,&X[i].b,&X[i].c);
}
sort(X,X+m,cmp);
for(int s=0;s<m;s++)
{
int x=get(X[s].a);
int y=get(X[s].b);
if(x==y)
{
printf("%d\n",X[s].c);
return 0;
}
int w=get(X[s].a+n);
int t=get(X[s].b+n);
f[x]=t;
f[y]=w;
}
printf("0\n");
return 0;
}

74
TYVJ/1403_chinaunix.cpp Normal file
View File

@ -0,0 +1,74 @@
#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <cstdlib>
using namespace std;
const int M = 100000;
const int N = 20000;
struct EDGE {
int a;
int b;
int v;
} edge[M];
int f[N * 2];
bool Compare(const EDGE &a, const EDGE &b)
{
return a.v < b.v;
}
int Find(int x)
{
if (f[x] == x) {
return f[x];
} else {
return f[x] = Find(f[x]);
}
}
int main()
{
int n, m;
ios::sync_with_stdio(false);
cin >> n;
cin >> m;
for (int i = 0; i < m; i++) {
cin >> edge[i].a;
cin >> edge[i].b;
cin >> edge[i].v;
}
for (int i = 0; i < n * 2; i++) {
f[i] = i;
}
sort(edge, edge + m, Compare);
for (int i = m - 1; i >= 0; i--) {
int x = Find(edge[i].a);
int y = Find(edge[i].b);
if (x == y) {
cout << edge[i].v << endl;
return 0;
}
int xx = Find(edge[i].a + n);
int yy = Find(edge[i].b + n);
f[x] = yy;
f[y] = xx;
}
cout << "0" << endl;
return 0;
}

40
TYVJ/1403_hzwer.cpp Normal file
View File

@ -0,0 +1,40 @@
#include <algorithm>
#include <iostream>
using namespace std;
int n,m,f[40001],x,y;
struct data
{
int a,b,c;
}e[100001];
int gz(const data &a,const data &b)
{
if(a.c>b.c)return 1;
else return 0;
}
int find(int x)
{
return f[x]==x?x:f[x]=find(f[x]);
}
int main()
{
cin>>n>>m;
for(int i=1;i<=m;i++)
cin>>e[i].a>>e[i].b>>e[i].c;
for(int i=1;i<=n*2;i++)
f[i]=i;
sort(e+1,e+m+1,gz);
for(int i=1;i<=m;i++)
{
x=find(e[i].a);
y=find(e[i].b);
if(x==y)
{
cout<<e[i].c;
return 0;
}
f[y] = find(e[i].a + n);
f[x] = find(e[i].b + n);
}
cout<<0;
return 0;
}

2
TYVJ/Readme.md Normal file
View File

@ -0,0 +1,2 @@
#太原成成中学 TYVJ
[Goto Home Page](http://www.tyvj.cn/ "Welcome to TYVJ 4.0")