Create 2104_famousdt.cpp

From http://blog.csdn.net/famousdt/article/details/7064866

POJ/2104_famousdt.cpp

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+/*==========================================================*\
+| 划分树
+\*==========================================================*/
+#define MAX_SIZE 100005
+int sorted[MAX_SIZE];//已经排好序的数据
+int toleft[25][MAX_SIZE];
+int tree[25][MAX_SIZE];
+void build_tree(int left, int right, int deep) 
+{
+	int i;
+	if (left == right) return ;
+	int mid = (left + right) >> 1;
+	int same = mid - left + 1; //位于左子树的数据
+	for (i = left; i <= right; ++i) {//计算放于左子树中与中位数相等的数字个数
+		if (tree[deep][i] < sorted[mid]) {
+			--same;
+		}
+	}
+	int ls = left;
+	int rs = mid + 1;
+	for (i = left; i <= right; ++i) {
+		int flag = 0;
+		if ((tree[deep][i] < sorted[mid]) || (tree[deep][i] == sorted[mid] && same > 0)) {
+			flag = 1;
+			tree[deep + 1][ls++] = tree[deep][i];
+			if (tree[deep][i] == sorted[mid])
+				same--;
+		} else {
+			tree[deep + 1][rs++] = tree[deep][i];
+		}
+		toleft[deep][i] = toleft[deep][i - 1]+flag;
+	}
+	build_tree(left, mid, deep + 1);
+	build_tree(mid + 1, right, deep + 1);
+}
+int query(int left, int right, int k, int L, int R, int deep)
+{
+	if (left == right)
+		return tree[deep][left];
+    int mid = (L + R) >> 1;
+	int x = toleft[deep][left - 1] - toleft[deep][L - 1];//位于left左边的放于左子树中的数字个数
+	int y = toleft[deep][right] - toleft[deep][L - 1];//到right为止位于左子树的个数
+	int ry = right - L - y;//到right右边为止位于右子树的数字个数
+	int cnt = y - x;//[left,right]区间内放到左子树中的个数
+	int rx = left - L - x;//left左边放在右子树中的数字个数
+	if (cnt >= k) {
+		//printf("sss %d %d %d\n", xx++, x, y);
+		return query(L + x, L + y - 1, k, L, mid, deep + 1);
+	}
+	else {
+		//printf("qqq %d %d %d\n", xx++, x, y);
+		return query(mid + rx + 1, mid + 1 + ry, k - cnt, mid + 1, R, deep + 1);
+	}
+}
+int main()
+{
+	int m, n;
+	int a, b, k;
+	int i;
+	while (scanf("%d%d", &m, &n) == 2) {
+		for (i = 1; i <= m; ++i) {
+			scanf("%d", &sorted[i]);
+			tree[0][i] = sorted[i];
+		}
+		sort(sorted + 1, sorted + 1 + m);
+		build_tree(1, m, 0);
+		for (i = 0; i < n; ++i) {
+			scanf("%d%d%d", &a, &b, &k);
+			printf("%d\n", query(a, b, k, 1, m, 0));
+		}
+	}
+	return 0;
+}