Create 1011_Richard.cpp

HDOJ/Multi-University Training Contest/2017/Team 2/1011_Richard.cpp

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+#include <cstdio>
+#include <iostream>
+#include <string>
+#include <vector>
+#include <algorithm>
+#include <deque>
+#include <queue>
+#include <map>
+#include <cstdlib>
+#include <cstring>
+using namespace std;
+bool plane[202][202];
+int main() {
+    int n;
+    int tx, ty;
+    map<int, vector<int> > point;
+    while (cin >> n) {
+        point.clear();
+        memset(plane, 0, sizeof(plane));
+        for (int i = 0; i < n; i++) {
+            cin >> tx >> ty;
+            tx += 100;
+            ty += 100;
+            plane[tx][ty] = true;
+            if (point.find(ty) == point.end()) {
+                vector<int> temp;
+                temp.push_back(tx);
+                point[ty] = temp;
+            }
+            else {
+                point[ty].push_back(tx);
+            }
+        }
+        int ans = 0;
+
+        //对每一行的点进行排序
+        for (auto ityi = point.begin(); ityi != point.end(); ityi++)
+            sort((*ityi).second.begin(), (*ityi).second.end());
+
+        //开始枚举，每个点都枚举自己右上象限的点
+        for (auto ityi = point.begin(); ityi != point.end(); ityi++) {
+            for (auto ityj = ityi ; ityj != point.end(); ityj++) {
+                for (auto itxi = (*ityi).second.begin(); itxi != (*ityi).second.end(); itxi++) {
+                    for (auto itxj = (*ityj).second.begin(); itxj != (*ityj).second.end(); itxj++) {
+                        if (*itxj < *itxi)
+                            continue;//左上方 剪枝
+                        int dx = *itxj - *itxi;
+                        int dy = ityj->first - ityi->first;
+                        int x = *itxi;
+                        int y = ityi->first;
+                        if (dx>0&&x - dy >= 0 && y + dx + dy <= 200 && plane[x - dy][y + dx] && plane[x + dx - dy][y + dx + dy]) {
+                            ans++;
+                            //cout << "P1 " << x << " " << y << endl;
+                            //cout << "P2" << *itxj << " " << ityj->first << endl;
+                            //cout << "P3" << x - dy << " " << y + dx << endl;
+                            //cout << "P4" << x + dx - dy << " " << y + dx + dy << endl;
+                        }
+                    }
+                }
+            }
+        }
+        cout << ans << endl;
+    }
+    return 0;
+}