mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
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206 lines
7.4 KiB
C++
206 lines
7.4 KiB
C++
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/*
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中国象棋棋盘，Alice有一个帅，Bob有一个将和一个马。如果Alice赢，输出
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"Lucky guy!"，否则就输出"Lose in x steps T.T!"，x表示从开始到结束双方走的步数和。
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一方获胜当且仅当自己的将（帅被对方吃掉）。特别注意，如果出现平局我们认为Alice获胜。
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Alice如果知道自己无法取胜就会尽量让比赛进行更多的步数。双方采取最优策略。
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*/
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#include <cstdio>
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#include <cmath>
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#include <algorithm>
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#include <iostream>
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#include <vector>
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#include <queue>
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#include <cstring>
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#include <cstdlib>
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#include <time.h>
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using namespace std;
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#define maxn 105
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const int move_ma[8][2] = {///马移动
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{-2, -1}, {-2, 1}, {-1, -2}, {1, -2},
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{-1, 2}, {1, 2}, {2, -1}, {2, 1}
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};
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const int no[4][2] = {///马脚
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{-1, 0}, {0, -1}, {0, 1}, {1, 0}
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};
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const int move_shuai[4][2] = {///将移动
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{1, 0}, {-1, 0}, {0, 1}, {0, -1}
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};
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int Max[maxn][10][10], cnt[maxn][10][10];
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int vis[maxn][10][10][2];
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///敌马的位置 敌将位置 我将位置 0:我先手 1:敌先手
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///状态下的失败步数
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///0表示我必胜
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int out[maxn][10][10];
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///我先走 这个状态后继状态中有多少种合法状态
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struct node {
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int a, b, c;///马位置 敌将位置 我将位置
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int id;///0:我先手 1:敌先手
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int step;///这个状态下失败的步数
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node (int _a, int _b, int _c, int _id, int _s) {
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a = _a, b = _b, c = _c, id = _id, step = _s;
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}
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};
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queue <node> q;
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bool balk (int now, int next, int i, int j) {
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int x = now/9, y = now%9;
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int xx = next/9, yy = next%9;
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//cout << x << " " << y << endl;
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//cout << xx << " " << yy << endl;
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for (int k = 0; k < 8; k++) {
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if (xx == x+move_ma[k][0] && yy == y+move_ma[k][1]) { //cout << k << endl;
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int xxx = x+no[k/2][0], yyy = y+no[k/2][1];
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//cout << xxx << " " << yyy << endl;
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if (xxx == i/3+7 && yyy == i%3+3) return 1;
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if (xxx == j/3 && yyy == j%3+3) return 1;
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}
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}
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return 0;
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}
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void bfs () {
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while (!q.empty ()) {
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node now = q.front (); q.pop ();
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int x = now.c/3, y = now.c%3;///我帅
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int ma_x = now.a/9, ma_y = now.a%9;///敌马
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if (now.id == 0) {///这一步是我先手 上一步是敌先手
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for (int i = 0; i < 4; i++) {///敌走将
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int xx = now.b/3+move_shuai[i][0], yy = now.b%3+move_shuai[i][1];///上一步敌将的位置
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if (xx < 0 || xx >= 3 || yy < 0 || yy >= 3) continue;
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if (vis[now.a][xx*3+yy][now.c][1] != -1) continue;
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if (xx+7 == ma_x && yy+3 == ma_y) continue;///敌将和马不重合
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vis[now.a][xx*3+yy][now.c][1] = now.step+1;
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q.push (node (now.a, xx*3+yy, now.c, 1, now.step+1));
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}
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for (int i = 0; i < 8; i++) {
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int xx = ma_x+move_ma[i][0], yy = ma_y+move_ma[i][1];
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if (xx < 0 || xx >= 10 || yy < 0 || yy >= 9) continue;
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if (vis[xx*9+yy][now.b][now.c][1] != -1) continue;
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if (xx == now.b/3+7 && yy == now.b%3+3) continue;///敌将和马不重合
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if (xx == x && yy == y+3) continue;///敌马和我帅不重合
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if (balk (xx*9+yy, now.a, now.b, now.c)) continue;///马脚
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vis[xx*9+yy][now.b][now.c][1] = now.step+1;
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q.push (node (xx*9+yy, now.b, now.c, 1, now.step+1));
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}
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}
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else {///上一步是我先手
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for (int i = 0; i < 4; i++) {
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int xx = x+move_shuai[i][0], yy = y+move_shuai[i][1];///上一步我的位置
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if (xx < 0 || xx >= 3 || yy < 0 || yy >= 3) continue;
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if (vis[now.a][now.b][xx*3+yy][0] != -1) continue;
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if (xx == ma_x && yy+3 == ma_y) continue;///上一步不可能重合
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Max[now.a][now.b][xx*3+yy] = max (Max[now.a][now.b][xx*3+yy], now.step);
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if (++cnt[now.a][now.b][xx*3+yy] == out[now.a][now.b][xx*3+yy]) {
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vis[now.a][now.b][xx*3+yy][0] = Max[now.a][now.b][xx*3+yy]+1;
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q.push (node (now.a, now.b, xx*3+yy, 0, vis[now.a][now.b][xx*3+yy][0]));
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}
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}
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}
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}
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}
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int relation (int x, int y, int i, int j, int who) {
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///0:我必败 1:我必胜 2:不一定
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int x1 = i/3, y1 = i%3;///敌将
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int x2 = j/3, y2 = j%3;///我帅
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y1 += 3, y2 += 3;
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if (y1 == y2) {///两王相对(中间没有马) 胜负立分
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if (y == y1) {
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if (x > x1+7 || x < x2) {
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if (who == 0) return 1;
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return 0;
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}
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else return 2;
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}
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if (who == 0)
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return 1;
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else
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return 0;
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}
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if (who == 1) {
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int d1 = abs (x-x2), d2 = abs (y-y2);
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if ((d1 == 1 && d2 == 2) || (d1 == 2 && d2 == 1))
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return 0;///被敌马吃掉
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return 2;
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}
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///马被吃
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if (x > 2 || y < 3 || y > 5) return 2;//马在外面
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if (y == y2) {
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if (x2-x == 1) {///在我将的下侧
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return 1;
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}
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if (x-x2 == 1) {///在我将的上侧
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if (y1 == y) return 2;///有敌将的保护
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return 1;
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}
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return 2;
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}
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if (x == x2 && abs (y-y2) == 1 && y <= 5 && y >= 3) {///在我将的左右侧
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if (y1 == y)
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return 2;///有敌方将的保护
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return 1;
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}
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return 2;
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}
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void init () {
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while (!q.empty ()) q.pop ();
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memset (vis, -1, sizeof vis);
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memset (Max, 0, sizeof Max);
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memset (out, 0, sizeof out);
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memset (cnt, 0, sizeof cnt);
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for (int x = 0; x < 10; x++) for (int y = 0; y < 9; y++) {///敌马位置
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for (int i = 0; i < 9; i++) {///敌将位置
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for (int j = 0; j < 9; j++) {///我将位置
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if ((y-3 == j%3 && x == j/3) || (y-3 == i%3 && x-7 == i/3))
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continue;///马和将重合
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int res0 = relation (x, y, i, j, 0);
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int res1 = relation (x, y, i, j, 1);
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if (!res0)
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vis[x*9+y][i][j][0] = 1, q.push (node (x*9+y, i, j, 0, 1));
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else if (res0 == 1) vis[x*9+y][i][j][0] = 0;
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if (!res1)
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vis[x*9+y][i][j][1] = 1, q.push (node (x*9+y, i, j, 1, 1));
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else if (res1 == 1) vis[x*9+y][i][j][1] = 0;
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for (int k = 0; k < 4; k++) {///我先走
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int next_x = j/3+move_shuai[k][0], next_y = j%3+move_shuai[k][1];
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if (next_x < 0 || next_x >= 3 || next_y < 0 || next_y >= 3) continue;
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if (next_x == x && next_y+3 == y) continue;///和马重合的状态已经计算过了
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out[x*9+y][i][j]++;
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}
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}
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}
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}
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bfs ();
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}
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int x, y, xx, yy, xxx, yyy;
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int main () {
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//freopen ("in", "r", stdin);
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//freopen ("out", "w", stdout);
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init (); int t;
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//cout << balk (21, 32, 0, 7) << endl;
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//cout << vis[30][1][6][1] << endl;
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//cout << vis[0][0][0][0] << endl;
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cin >> t;
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int who;
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//输入敌马 敌将 我将坐标 先手的人
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while (t--) {
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cin >> x >> y >> xx >> yy >> xxx >> yyy >> who;
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xx -= 7, yy -= 3;
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yyy -= 3;
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int res = vis[x*9+y][xx*3+yy][xxx*3+yyy][who];
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if (res == 0) {
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cout << "Lucky guy!" << endl;
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}
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else
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cout << "Lose in " << res << " steps T.T!" << endl;
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}
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return 0;
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}
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