OJ-Problems-Source/LuoGu/2415_doctor_godder.cpp

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#include<cstdio>
#include<iostream>
#include<math.h>
using namespace std;
double sum=0,sum1=0;
int a[1100],num=0;
int main()
{
while (cin>>a[++num])
{
/*for (int i=1;i<=num-1;++i)
if (a[i]==a[num])
{
--num;
break;
}*/
}
--num;
for (int i=1;i<=num;++i) sum1+=a[i];
printf("%0.0lf",sum1*pow(2,num-1));
return 0;
}