OJ-Problems-Source/HDOJ/4563_autoAC.cpp

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#include <algorithm>
#include <iostream>
#include <string>
#include <string.h>
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <vector>
#include <queue>
#include <stack>
#include <cmath>
#include <list>
#include <set>
#include <map>
using namespace std;
#define N 100010
#define E 100010
#define ll long long
const int INF =0x3fffffff;
const int PRIME =999983;
const int MOD =1000000007;
const int MULTI =1000000007;
const double EPS=1e-8;
#define CUBE(x) ((x)*(x)*(x))
#define SQ(x) ((x)*(x))
#define ALL(x) x.begin(),x.end()
#define CLR(x,a) memset(x,a,sizeof(x))
#define maxAry(a,n) max_element(a,a+(n))
#define minAry(a,n) min_element(a,a+(n))
inline bool isodd(int x){return x&1;}
inline bool isodd(ll x) {return x&1;}
double dp[110];
int vx[110],vy[110];
int n,L;
double gao(int x)
{
fill(dp,dp+L+1,-1);
dp[0]=0;
for(int i=0;i<n;i++){
if(i==x) continue;
for(int j=L;j>=0;j--){
for(int k=0;k<=100;k++){
if(j-vx[i]*k<0 || dp[j-vx[i]*k]==-1) continue;
if(dp[j]==-1) dp[j]=dp[j-vx[i]*k]+vy[i]*k-0.5*9.8*SQ(k);
else dp[j]=max(dp[j],dp[j-vx[i]*k]+vy[i]*k-0.5*9.8*SQ(k));
}
}
}
double ans=-INF;
for(int i=0;i<=L;i++){
if(dp[i]==-1) continue;
double t=1.0*(L-i)/vx[x];
ans=max(ans,dp[i]+vy[x]*t-0.5*9.8*SQ(t));
}
return ans;
}
int main()
{
int re,Case=1;
double ans;
scanf("%d",&re);
while(re--){
scanf("%d%d",&n,&L);
for(int i=0;i<n;i++)
scanf("%d%d",&vx[i],&vy[i]);
ans=-INF;
for(int i=0;i<n;i++)
ans=max(ans,gao(i));
printf("Case %d: %.3lf\n",Case++,ans);
}
return 0;
}