Kiritow/OJ-Problems-Source
1
0
Fork 0
mirror of https://github.com/Kiritow/OJ-Problems-Source.git synced 2024-03-22 13:11:29 +08:00
Code Issues Projects Releases Wiki Activity
791fc60b5c
OJ-Problems-Source/.ACM-Templates/TXTs/应用.txt

211 lines
6.7 KiB
Plaintext
Raw Normal View History

Add files via upload
2016-11-22 09:38:35 +08:00
//Joseph<70><68><EFBFBD><EFBFBD> O(n)
int Joseph(int n, int m, int s) {
int ret = s - 1;
for (int i = 2; i <= n; i++) { ret = (ret + m) % i; }
return ret + 1;
}
//O(logn) 0 <= k < n
int Joseph(int n, int m, int k) {
if (m == 1) { return n - 1; }
for (k = k * m + m - 1; k >= n; k = k - n + (k - n) / (m - 1));
return k;
}
//<2F><><EFBFBD><EFBFBD>չ<EFBFBD><D5B9> fac[]Ϊ<>׳<EFBFBD> 0 <= ans
ll Cantor(char *s) {
ll ans = 0;
for (int i = 0, len = strlen(s); i < len; i++) {
int cnt = 0;
for (int j = i + 1; j < len; j++) { if (s[j] < s[i]) { cnt++; } }
ans += cnt * fac[len - i - 1];
}
return ans;
}
//<2F><><EFBFBD><EFBFBD>չ<EFBFBD><D5B9><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD> 1 <= k <= n!
vector<int> revCantor(ll n, ll k) {
vector<int> v, ret; k--;
for (int i = 1; i <= n; i++) { v.push_back(i); }
for (int i = n; i >= 1; i--) {
ll t = k / fac[i - 1]; k %= fac[i - 1];
sort(v.begin(), v.end());
ret.push_back(v[t]); v.erase(v.begin() + t);
}
return ret;
}
//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ȫΪid<69><64><EFBFBD>Ӿ<EFBFBD><D3BE><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
//<2F><><EFBFBD><EFBFBD>ջ O(nm)
int n, m, a[N][N], h[N];
int solve(int id) {
int ans = 0;
memset(h, 0, sizeof(h));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) { h[j] = a[i][j] == id ? h[j] + 1 : 0; }
stack<int> st; st.push(0);
for (int j = 1; j <= m + 1; j++) {
while (h[j] < h[st.top()]) {
int t = h[st.top()]; st.pop();
int w = j - st.top() - 1;
ans = max(ans, t * w);
}
st.push(j);
}
}
return ans;
}
//dp <20><><EFBFBD>߷<EFBFBD> O(nm)
int n, m, a[N][N], l[N], r[N], h[N];
int solve(int id) {
int ans = 0;
for (int i = 1; i <= m; i++) { l[i] = 1; r[i] = m; h[i] = 0; }
for (int i = 1; i <= n; i++) {
for (int j = 1, mxl = 1; j <= m; j++) {
if (a[i][j] == id) { h[j]++; l[j] = max(l[j], mxl); }
else { h[j] = 0; l[j] = 1; r[j] = m; mxl = j + 1; }
}
for (int j = m, mxr = m; j >= 1; j--) {
if (a[i][j] == id) { r[j] = min(r[j], mxr); ans = max(ans, (r[j] - l[j] + 1) * h[j]); }
else { mxr = j - 1; }
}
}
return ans;
}
//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ǰ<EFBFBD><C7B0> + <20><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
void getPost(char *pre, char *in, int len) {
if (len == 0) { return; }
int root = 0;
for (; root < len && in[root] != *pre; root++);
getPost(pre + 1, in, root);
getPost(pre + root + 1, in + root + 1, len - root - 1);
putchar(*pre);
}
//<2F><>1<EFBFBD><31>n֮<6E><D6AE>1<EFBFBD>ĸ<EFBFBD><C4B8><EFBFBD>
ll countOne(ll n) {
ll ret = 0;
for (ll m = 1; m <= n; m *= 10) {
ll a = n / m, b = n % m;
ret += (a + 8) / 10 * m + (a % 10 == 1) * (b + 1);
}
return ret;
}
//<2F><>1<EFBFBD><31>n<EFBFBD><6E><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ֵ<EFBFBD><D6B5><EFBFBD>λ<EFBFBD>͵ĺ<CDB5> <20><>λDP
char t[N];
ll dp[N][N][N];
ll countDigit(char *s) {
ll ret = 0;
for (int i = 1, n = strlen(s); i <= n; i++) { t[i] = s[i - 1] - '0'; }
for (int i = 0; i <= t[1]; i++) { dp[1][i][i == t[1]] = 1; }
for (int i = 1; i < n; i++) {
for (int j = 1; j <= 900; j++) {
if (dp[i][j][0]) {
for (int k = 0; k <= 9; k++) { dp[i + 1][j + k][0] += dp[i][j][0]; dp[i + 1][j + k][0] %= M; }
}
if (dp[i][j][1]) {
for (int k = 0; k <= t[i + 1]; k++) { dp[i + 1][j + k][k == t[i + 1]] += dp[i][j][1]; dp[i + 1][j + k][k == t[i + 1]] %= M; }
}
}
}
for (int j = 1; j <= 900; j++) { ret += dp[n][j][0] * dp[n][j][1] % M; ret %= M; }
return ret;
}
//<2F><>hash
int hs[N], P[N]; //һЩ<D2BB><D0A9><EFBFBD><EFBFBD>
void dfs(int u, int p) {
vector<int> t; t.push_back(1);
for (int i = 0; i < (int)e[u].size(); i++) {
int v = e[u][i];
if (v == p) { continue; }
dfs(v, u); t.push_back(hs[v]);
}
sort(t.begin(), t.end()); hs[u] = 0;
for (int i = 0; i < (int)t.size(); i++) { hs[u] += t[i] * P[i]; }
}
for (int j = 1; j <= n; j++) {
dfs(j, 0); //cout << j << ' ' << hs[j] << endl;
}
sort(hs[i] + 1, hs[i] + n + 1); //<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ַ<EFBFBD><D6B7><EFBFBD><EFBFBD><EFBFBD> O(n^1.5)
int n, f[777] = {0, 1, 2, 5, 7}, g[N] = {1};
int main() {
for (int i = 5; i < 777; i++) { f[i] = 3 + 2 * f[i - 2] - f[i - 4]; }
while (~scanf("%d", &n)) {
for (int i = 1; i <= n; i++) {
for (int j = 1; f[j] <= i; j++) {
if ((j + 1) >> 1 & 1) { g[i] = (g[i] + g[i - f[j]]) % M; }
else { g[i] = ((g[i] - g[i - f[j]]) % M + M) % M; }
}
}
printf("%d\n", g[n]);
}
}
//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>gcd<63><64>Ԥ<EFBFBD><D4A4><EFBFBD><EFBFBD>
int l[N], v[N];
void calGCD {
for (int i = 1, j; i <= n; i++) {
for (v[i] = a[i], j = l[i] = i; j; j = l[j] - 1) {
v[j] = __gcd(v[j], a[i]);
while (l[j] > 1 && __gcd(a[i], v[l[j] - 1]) == __gcd(a[i], v[j])) { l[j] = l[l[j] - 1]; }
//[l[j]...j, i]<5D><><EFBFBD><EFBFBD><EFBFBD>ڵ<EFBFBD>ֵ<EFBFBD><D6B5>gcd<63><64>Ϊv[j]
}
}
}
//С<><D0A1>ת<EFBFBD><D7AA>Ϊ<EFBFBD><CEAA><EFBFBD><EFBFBD>
//<2F><>С<EFBFBD><D0A1>ת<EFBFBD><D7AA>Ϊ<EFBFBD><CEAA><EFBFBD><EFBFBD>, ѭ<><D1AD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>()<29><>ʾ
void work(char str[]) {
int len = strlen(str), cnt1 = 0, cnt2 = 0;
ll a = 0, b = 0; bool flag = false;
for (int i = 2; i < len; i++) {
if (str[i] == '(') { break; }
a = a * 10 + str[i] - '0'; cnt1++;
}
for (int i = 2; i < len; i++) {
if (str[i] == '(' || str[i] == ')') { flag = true; continue; }
b = b * 10 + str[i] - '0'; cnt2++;
}
ll p = b - a, q = 0; cnt2 -= cnt1;
if (!flag) { p = b; q = 1; cnt2 = 0; }
for (int i = 0; i < cnt2; i++) { q = q * 10 + 9; }
for (int i = 0; i < cnt1; i++) { q = q * 10; }
ll g = gcd(p, q);
printf("%I64d/%I64d\n", p / g, q / g);
}
//<2F><><EFBFBD><EFBFBD>ת<EFBFBD><D7AA>ΪС<CEAA><D0A1>
//<2F><><EFBFBD><EFBFBD>: <20><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>a / b(<28><><EFBFBD><EFBFBD>0 < a < b<><62>(a, b) = 1)<29>ܱ<EFBFBD>ʾ<EFBFBD>ɴ<EFBFBD>ѭ<EFBFBD><D1AD>С<EFBFBD><D0A1><EFBFBD>ij<EFBFBD>Ҫ<EFBFBD><D2AA><EFBFBD><EFBFBD><EFBFBD><EFBFBD>(b, 10) = 1
//<2F><><EFBFBD><EFBFBD>: <20><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>a / b, 0 < a < b, (a, b) = 1, b = (2 ^ <20><>) * (5 ^ <20><>) * b1, (b1, 10) = 1,
// b1<62><31><EFBFBD><EFBFBD><EFBFBD><EFBFBD>1<EFBFBD><31><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>²<EFBFBD>ȫΪ<C8AB>㣬<EFBFBD><E3A3AC>a / b<><62><EFBFBD>Ա<EFBFBD>ʾΪ<CABE><CEAA>ѭ<EFBFBD><D1AD>С<EFBFBD><D0A1><EFBFBD><EFBFBD><EFBFBD>䲻ѭ<E4B2BB><D1AD><EFBFBD><EFBFBD>λ<EFBFBD><CEBB>Ϊu = max(<28><>, <20><>)
void work(int n) {
bool flag = false;
int ans[N] = { 0 }, f[N] = { 0, 1 }, k = 1, cnt = 0;
if (n < 0) { n = -n; flag = 1; }
while (k && n != 1) {
k *= 10; ans[cnt++] = k / n; k %= n;
if (f[k]) { break; }
f[k] = 1;
}
if (flag) { printf("-"); }
if (n == 1) { puts("1"); }
else {
printf("0.");
for (int i = 0; i < cnt; i++) { printf("%d", ans[i]); }
puts("");
}
}
//ˮ<>ɻ<EFBFBD><C9BB><EFBFBD> A023052 Powerful numbers(3): numbers n that are the sum of some fixed power of their digits.
int Nar[] = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 4150, 4151, 8208, 9474, 54748, 92727, 93084,
194979, 548834, 1741725, 4210818, 9800817, 9926315, 14459929, 24678050, 24678051, 88593477
};
//<2F><><EFBFBD><EFBFBD> A000396 Perfect numbers n: n is equal to the sum of the proper divisors of n.
string str[] = {
"6",
"28",
"496",
"8128",
"33550336",
"8589869056",
"137438691328",
"2305843008139952128",
"2658455991569831744654692615953842176",
"191561942608236107294793378084303638130997321548169216",
"13164036458569648337239753460458722910223472318386943117783728128",
"14474011154664524427946373126085988481573677491474835889066354349131199152128",
"23562723457267347065789548996709904988477547858392600710143027597506337283178622239730365539602600561360255566462503270175052892578043215543382498428777152427010394496918664028644534128033831439790236838624033171435922356643219703101720713163527487298747400647801939587165936401087419375649057918549492160555646976"
};
Reference in New Issue Copy Permalink