OJ-Problems-Source/POJ/1661_jdplus.cpp

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2016-09-01 20:23:38 +08:00
#include <stdio.h>
#include <stdlib.h>
#define MAXN 1010
#define INF 9000000
typedef struct platform{
int x1;
int x2;
int high;
}Platform;
int compare (const void * p, const void * q){
Platform * p1 = (Platform *)p;
Platform * q1 = (Platform *)q;
return p1->high - q1->high;
}
int Min (int a, int b){
return (a < b) ? a : b;
}
int N, X, Y, MAX;
Platform plat[MAXN];
int dp[MAXN][2]; //dp[i][0]、dp[i][1]分别表示从第i个平台左、右边到地面的最短时间
void LeftMinTime (int i){ //计算从平台i左边到地面的最短时间
int k = i - 1;
while (k > 0 && plat[i].high - plat[k].high <= MAX){
//如果平台i左边下面有平台且两者相距不超过MAX
if (plat[i].x1 >= plat[k].x1 && plat[i].x1 <= plat[k].x2){
dp[i][0] = plat[i].high - plat[k].high +
Min (plat[i].x1 - plat[k].x1 + dp[k][0], plat[k].x2 - plat[i].x1 + dp[k][1]);
return;
}
else
--k;
}
//如果平台i左边下面没有平台或者两者相距超过了MAX
if (plat[i].high - plat[k].high > MAX)
dp[i][0] = INF;
else
dp[i][0] = plat[i].high;
}
void RightMinTime (int i){ //计算从平台i右边到地面的最短时间
int k = i - 1;
while (k > 0 && plat[i].high - plat[k].high <= MAX){
//如果平台i右边下面有平台且两者相距不超过MAX
if (plat[i].x2 >= plat[k].x1 && plat[i].x2 <= plat[k].x2){
dp[i][1] = plat[i].high - plat[k].high +
Min (plat[i].x2 - plat[k].x1 + dp[k][0], plat[k].x2 - plat[i].x2 + dp[k][1]);
return;
}
else
--k;
}
//如果平台i右边下面没有平台或者两者相距超过了MAX
if (plat[i].high - plat[k].high > MAX)
dp[i][1] = INF;
else
dp[i][1] = plat[i].high;
}
int ShortestTime (){
int i, j;
for (i=1; i<=N+1; ++i){
LeftMinTime (i);
RightMinTime (i);
}
return Min (dp[N+1][0], dp[N+1][1]);
}
int main(void){
int t;
int i;
while (scanf ("%d", &t) != EOF){
while (t-- != 0){
scanf ("%d%d%d%d", &N, &X, &Y, &MAX);
for (i=1; i<=N; ++i){
scanf ("%d%d%d", &plat[i].x1, &plat[i].x2, &plat[i].high);
}
plat[0].high = 0;
plat[0].x1 = -20000;
plat[0].x2 = 20000;
plat[N+1].high = Y;
plat[N+1].x1 = X;
plat[N+1].x2 = X;
//根据平台高度按从低到高排序
qsort (plat, N+2, sizeof(Platform), compare);
printf ("%d\n", ShortestTime());
}
}
return 0;
}