mirror of
https://github.com/Kiritow/OJ-Problems-Source.git
synced 2024-03-22 13:11:29 +08:00
99 lines
2.1 KiB
C++
99 lines
2.1 KiB
C++
|
#include <cstdio>
|
||
|
#include <cstring>
|
||
|
#include <cmath>
|
||
|
#include <cstdlib>
|
||
|
#include <iostream>
|
||
|
#include <algorithm>
|
||
|
#include <queue>
|
||
|
#include <map>
|
||
|
#include <set>
|
||
|
#include <vector>
|
||
|
#include <cctype>
|
||
|
using namespace std;
|
||
|
const int mod=6;
|
||
|
struct matrix{
|
||
|
int f[6][6];
|
||
|
};
|
||
|
int A[1001][6],B[6][1001],C[1001][6],D[1001][1001];
|
||
|
matrix mul(matrix a,matrix b,int n)
|
||
|
{
|
||
|
matrix c;
|
||
|
memset(c.f,0,sizeof(c.f));
|
||
|
int i,j,k;
|
||
|
for(i=0;i<n;i++)
|
||
|
{
|
||
|
for(j=0;j<n;j++)
|
||
|
{
|
||
|
for(k=0;k<n;k++)
|
||
|
{
|
||
|
c.f[i][j]+=a.f[i][k]*b.f[k][j];
|
||
|
}
|
||
|
c.f[i][j]%=mod;
|
||
|
}
|
||
|
}
|
||
|
return c;
|
||
|
}
|
||
|
matrix pow_mod(matrix a,int b,int n)
|
||
|
{
|
||
|
matrix s;
|
||
|
memset(s.f,0,sizeof(s.f));
|
||
|
for(int i=0;i<n;i++)s.f[i][i]=1;
|
||
|
while(b)
|
||
|
{
|
||
|
if(b&1)s=mul(s,a,n);
|
||
|
a=mul(a,a,n);
|
||
|
b=b>>1;
|
||
|
}
|
||
|
return s;
|
||
|
}
|
||
|
int main()
|
||
|
{
|
||
|
int n,K;
|
||
|
while(scanf("%d%d",&n,&K)!=EOF)
|
||
|
{
|
||
|
if(n==0&&K==0)break;
|
||
|
int i,j,k;
|
||
|
for(i=0;i<n;i++)
|
||
|
for(j=0;j<K;j++)
|
||
|
scanf("%d",&A[i][j]);
|
||
|
for(i=0;i<K;i++)
|
||
|
for(j=0;j<n;j++)
|
||
|
scanf("%d",&B[i][j]);
|
||
|
matrix e,g;
|
||
|
memset(e.f,0,sizeof(e.f));
|
||
|
for(i=0;i<K;i++)
|
||
|
{
|
||
|
for(j=0;j<K;j++)
|
||
|
{
|
||
|
for(k=0;k<n;k++)
|
||
|
e.f[i][j]+=B[i][k]*A[k][j];
|
||
|
e.f[i][j]%mod;
|
||
|
}
|
||
|
}
|
||
|
e=pow_mod(e,n*n-1,K);
|
||
|
memset(C,0,sizeof(C));
|
||
|
for(i=0;i<n;i++)
|
||
|
{
|
||
|
for(j=0;j<K;j++)
|
||
|
{
|
||
|
for(k=0;k<K;k++)
|
||
|
C[i][j]+=A[i][k]*e.f[k][j];
|
||
|
C[i][j]%=mod;
|
||
|
}
|
||
|
}
|
||
|
int ans=0;
|
||
|
memset(D,0,sizeof(D));
|
||
|
for(i=0;i<n;i++)
|
||
|
{
|
||
|
for(j=0;j<n;j++)
|
||
|
{
|
||
|
for(k=0;k<K;k++)
|
||
|
D[i][j]+=C[i][k]*B[k][j];
|
||
|
ans+=D[i][j]%mod;
|
||
|
}
|
||
|
}
|
||
|
printf("%d\n",ans);
|
||
|
}
|
||
|
return 0;
|
||
|
}
|